使用PHP显示MySQL数据库中的所有表?如何获取表格至 OP
我正在尝试显示数据库中的所有表。我试过这个:
$sql = "SHOW TABLES";
$result = $conn->query($sql);
$tables = $result->fetch_assoc();
foreach($tables as $tmp)
{
echo "$tmp <br>";
}
但它只给了我一个表名,我知道有2个。我做错了什么?
我正在尝试显示数据库中的所有表。我试过这个:
$sql = "SHOW TABLES";
$result = $conn->query($sql);
$tables = $result->fetch_assoc();
foreach($tables as $tmp)
{
echo "$tmp <br>";
}
但它只给了我一个表名,我知道有2个。我做错了什么?
SHOW TABLES
mysql> USE test;
Database changed
mysql> SHOW TABLES;
+----------------+
| Tables_in_test |
+----------------+
| t1 |
| t2 |
| t3 |
+----------------+
3 rows in set (0.00 sec)
SHOW TABLES IN db_name
mysql> SHOW TABLES IN another_db;
+----------------------+
| Tables_in_another_db |
+----------------------+
| t3 |
| t4 |
| t5 |
+----------------------+
3 rows in set (0.00 sec)
mysql> SELECT TABLE_NAME
FROM information_schema.TABLES
WHERE TABLE_SCHEMA = 'another_db';
+------------+
| TABLE_NAME |
+------------+
| t3 |
| t4 |
| t5 |
+------------+
3 rows in set (0.02 sec)
你只抓取了1行。修复如下:
while ( $tables = $result->fetch_array())
{
echo $tmp[0]."<br>";
}
我认为,information_schema会比SHOW TABLES
SELECT TABLE_NAME
FROM information_schema.TABLES
WHERE TABLE_SCHEMA = 'your database name'
while ( $tables = $result->fetch_assoc())
{
echo $tables['TABLE_NAME']."<br>";
}
试试这个:
SHOW TABLES FROM nameOfDatabase;