PHP PDO 预准备语句 -- MySQL LIKE query
我正在尝试通过php的PDO类(mysql驱动程序)进行搜索。我有以下查询使用MySQL客户端(表名称已更改以保护无辜者):
SELECT hs.hs_pk,
hs.hs_text,
hs.hs_did,
hd.hd_did,
hd.hd_text,
hv.hv_text,
hc.hc_text
FROM hs
LEFT JOIN hd
ON hs.hs_did = hd.hd_did
LEFT JOIN hd
ON hd.hd_vid = hv.hv_id
LEFT JOIN hc
ON hd.hd_pclass = hc.hc_id
WHERE hs.hs_text LIKE "%searchTerm%"
LIMIT 25;
这与超级按钮一样工作,无论我使用哪个搜索词。但是,当我移动到php时,我无法让它返回任何内容。我已经尝试了几种不同的语法,这些语法似乎合乎逻辑地起作用,但我尝试过的语法都不起作用。这是我现有的代码:
$handle = fopen('/foo/bar/test.log', 'w+');
fwrite($handle, "doSearch, with search term: $searchTerm\n");
$sql =
'SELECT hs.hs_pk,
hs.hs_text,
hs.hs_did,
hd.hd_did,
hd.hd_text,
hv.hv_text,
hc.hc_text
FROM hs
LEFT JOIN hd
ON hs.hs_did = hd.hd_did
LEFT JOIN hd
ON hd.hd_vid = hv.hv_id
LEFT JOIN hc
ON hd.hd_pclass = hc.hc_id
WHERE hs.hs_text LIKE :searchTerm
LIMIT 25';
try {
$dbh = new PDO('mysql:host=localhost;dbname=awdb', "user", "password");
fwrite($handle, "connected to DB\n");
$prep = $dbh->prepare($sql);
$ret = $prep->execute(array(':searchTerm' => '"%'.$searchTerm.'%"'));
while ($row = $prep->fetch(PDO::FETCH_ASSOC)) {
$i++;
$result[$i]['subText'] = $row['hs_pk'];
$result[$i]['subText'] = $row['hs_text'];
$result[$i]['subDid'] = $row['hs_did'];
$result[$i]['devDid'] = $row['hd_did'];
$result[$i]['devText'] = $row['hd_text'];
$result[$i]['vendorText'] = $row['hv_text'];
$result[$i]['classText'] = $row['hc_text'];
}
$dbh = null;
}
catch (PDOException $e) {
print "Error!: " . $e->getMessage() . "<br/>";
die();
}
我也尝试了以下方法(SQL WHERE子句和prep->execute行都是这些变化):
WHERE hs.hs_text LIKE CONCAT(\'%\', ?, \'%\')
$ret = $prep->execute(array($searchTerm));
WHERE hs.hs_text LIKE "%:searchTerm%"
$ret = $prep->execute(array(':searchTerm' => $searchTerm));
WHERE hs.hs_text LIKE ":searchTerm"
$ret = $prep->execute(array(':searchTerm' => '%'.$searchTerm.'%'));
等。。。