C、Java 或 PHP 中的语音识别？[已关闭]

有没有众所周知的C或Java或PHP框架来做语音识别应用程序？麦克风音频输入，它将识别英语单词。如伪代码：

Speech s = new Speech();
s.input(micStream);
result = s.recognise("Hello");
if (result) { printf("Matched hello"); } else { printf("No match found"); }

跟进：

下载这个： 狮身人面像4 / 1.0%20beta6/

2. 添加库

3. 复制和粘贴代码：

   a） xml 文件放在某个地方，可以从代码中加载：

   https://gist.github.com/2551321

   b） 使用这个：

   package edu.cmu.sphinx.demo.hellowrld;
   import edu.cmu.sphinx.frontend.util.Microphone;
   import edu.cmu.sphinx.recognizer.Recognizer;
   import edu.cmu.sphinx.result.Result;
   import edu.cmu.sphinx.util.props.ConfigurationManager;
   import java.io.IOException;
   import java.util.logging.Level;
   import java.util.logging.Logger;
   import models.Tts;
   
   public class Speech {
   
     public static void main(String[] args) {
       ConfigurationManager cm;
   
       if (args.length > 0) {
           cm = new ConfigurationManager(args[0]);
       } else {
           ///tmp/helloworld.config.xml
           cm = new ConfigurationManager(Speech.class.getResource("speech.config.xml"));
   
       }
       Recognizer recognizer = (Recognizer) cm.lookup("recognizer");
       recognizer.allocate();
   
       Microphone microphone = (Microphone) cm.lookup("microphone");
       if (!microphone.startRecording()) {
           System.out.println("Cannot start microphone.");
           recognizer.deallocate();
           System.exit(1);
       }
   
       System.out.println("Say: (Hello | call) ( Naam | Baam | Caam | Some )");
   
       while (true) {
           System.out.println("Start speaking. Press Ctrl-C to quit.\n");
   
           Result result = recognizer.recognize();
   
           if (result != null) {
               String resultText = result.getBestFinalResultNoFiller();
               System.out.println("You said: " + resultText + '\n');
   
                   Tts ts = new Tts();
                   try {
                       ts.load();
                       ts.say("Did you said: " + resultText);
                   } catch (IOException ex) {
   
                   } 
           } else {
               System.out.println("I can't hear what you said.\n");
           }
       }
     }
   }