ZF2:在控制器中获取 url 参数

2022-08-30 16:12:52

我经历过Zend Framework 1,并且我已经使用该框架构建了一些应用程序。

现在,我正在试验Zend Framework 2,但我卡在url参数上。我是这样设置路由的:

// Setup for router and routes
'Zend\Mvc\Router\RouteStack' => array(
    'parameters' => array(
        'routes' => array(
            'default' => array(
                'type'    => 'Zend\Mvc\Router\Http\Segment',
                'options' => array(
                    'route'    => '/[:slug]',
                    'constraints' => array(
                    'slug' => '[a-zA-Z][a-zA-Z0-9_\/-]*'
                    ),
                'defaults' => array(
                    'controller' => 'Htmlsite\Controller\BootController',
                    'action'     => 'index',
                    'slug' => 'home'
                    ),
                ),
            ),
        'home' => array(
            'type' => 'Zend\Mvc\Router\Http\Literal',
            'options' => array(
                'route'    => '/',
                'defaults' => array(
                    'controller' => 'Htmlsite\Controller\BootController',
                    'action'     => 'index',
                    ),
                ),
            ),
        ),
    ),
),

正如你所看到的,我试图制作一个可变的slug。如何访问此变量?


答案 1

或者简单地说:

$slug= $this->params('slug');

答案 2

为什么不是这个:

$this->params()->fromRoute('slug');

推荐