如何获取调用类的名称(PHP 格式)
2022-08-30 15:47:58
define('anActionType', 1);
$actionTypes = array(anActionType => 'anActionType');
class core {
public $callbacks = array();
public $plugins = array();
public function __construct() {
$this->plugins[] = new admin();
$this->plugins[] = new client();
}
}
abstract class plugin {
public function registerCallback($callbackMethod, $onAction) {
if (!isset($this->callbacks[$onAction]))
$this->callbacks[$onAction] = array();
global $actionTypes;
echo "Calling $callbackMethod in $callbacksClass because we got {$actionTypes[$onAction]}" . PHP_EOL;
// How do I get $callbacksClass?
$this->callbacks[$onAction][] = $callbackMethod;
}
}
class admin extends plugin {
public function __construct() {
$this->registerCallback('onTiny', anActionType);
}
public function onTiny() { echo 'tinyAdmin'; }
}
class client extends plugin {
public function __construct() {
$this->registerCallback('onTiny', anActionType);
}
public function onTiny() { echo 'tinyClient'; }
}
$o = new core();
$callbacksClass
应为管理员或客户端。还是我在这里完全错过了重点,应该以另一种方式进行?应该注意的是,我只接受一个不需要我将类名作为参数发送到registerCallback方法的答案。