在数组中查找缺失的数字

php arrays

2022-08-30 18:41:33

我正在尝试在如下所示的数组中查找每个缺失的数字。

Array ( 
  [0] => 1 [1] => 2 [2] => 3 [3] => 4 [4] => 5 [5] => 6 [6] => 7 [7] => 8 
  [8] => 9 [9] => 10 [10] => 11 [11] => 12 [12] => 13 [13] => 14 [14] => 15 
  [15] => 16 [16] => 17 [17] => 18 [18] => 19 [19] => 20 [20] => 21 [21] => 22 
  [22] => 23 [23] => 24 [24] => 25 [25] => 26 [26] => 27 [27] => 28 [28] => 29 
  [29] => 30 [30] => 31 [31] => 32 [32] => 33 [33] => 34 [34] => 35 [35] => 36 
  [36] => 37 [37] => 38 [38] => 39 [39] => 40 [40] => 41 [41] => 42 [42] => 43 
  [43] => 44 [44] => 45 [45] => 46 [46] => 47 [47] => 48 [48] => 49 [49] => 50 
  [50] => 51 [51] => 52 [52] => 53 [53] => 54 [54] => 55 [55] => 56 [56] => 57 
  [57] => 58 [58] => 59 [59] => 60 [60] => 61 [61] => 62 [62] => 63 [63] => 64 
  [64] => 67 [65] => 68 [66] => 69 
)

数字，在这个特定的数组中是缺失的。6566

我的问题是，在PHP的帮助下，我如何找出哪些数字丢失了。具体来说，我需要找出的是缺失的最低数字。

原因：因为这样我就可以将该号码作为 ID 分配给成员。

答案 1

您可以使用和功能作为：array_diffrange

// given array. 3 and 6 are missing.
$arr1 = array(1,2,4,5,7); 

// construct a new array:1,2....max(given array).
$arr2 = range(1,max($arr1));                                                    

// use array_diff to get the missing elements 
$missing = array_diff($arr2,$arr1); // (3,6)

答案 2

我假设数字是数组的元素，而不是键。我还假设这些数字从1开始，而不是从0开始。

$Expected = 1;
foreach ($InputArray as $Key => $Number)
{
   if ($Expected != $Number)
   {
       break;
   }
   $Expected++;
}

echo $Number;