PHP PDO 与 foreach 和 fetch
下面的代码:
<?php
try {
$dbh = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password);
echo "Connection is successful!<br/>";
$sql = "SELECT * FROM users";
$users = $dbh->query($sql);
foreach ($users as $row) {
print $row["name"] . "-" . $row["sex"] ."<br/>";
}
foreach ($users as $row) {
print $row["name"] . "-" . $row["sex"] ."<br/>";
}
$dbh = null;
}
catch (PDOexception $e) {
echo "Error is: " . $e-> etmessage();
}
输出:
Connection is successful!
person A-male
person B-female
运行“foreach”两次不是我的目的,我只是好奇为什么两个“foreach”语句只输出一次结果?
以下是类似的情况:
<?php
try {
$dbh = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password);
echo "Connection is successful!<br/>";
$sql = "SELECT * FROM users";
$users = $dbh->query($sql);
foreach ($users as $row) {
print $row["name"] . "-" . $row["sex"] ."<br/>";
}
echo "<br/>";
$result = $users->fetch(PDO::FETCH_ASSOC);
foreach($result as $key => $value) {
echo $key . "-" . $value . "<br/>";
}
$dbh = null;
}
catch (PDOexception $e) {
echo "Error is: " . $e-> etmessage();
}
输出:
Connection is successful!
person A-male
person B-female
SCREAM: Error suppression ignored for
Warning: Invalid argument supplied for foreach()
但是当我从上面的代码中删除第一个“foreach”时,输出将变得正常:
<?php
try {
$dbh = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password);
echo "Connection is successful!<br/>";
$sql = "SELECT * FROM users";
$users = $dbh->query($sql);
echo "<br/>";
$result = $users->fetch(PDO::FETCH_ASSOC);
foreach($result as $key => $value) {
echo $key . "-" . $value . "<br/>";
}
$dbh = null;
}
catch (PDOexception $e) {
echo "Error is: " . $e-> etmessage();
}
输出:
Connection is successful!
user_id-0000000001
name-person A
sex-male
为什么会发生这种情况?