从 base64 字符串获取图像

php

2022-08-30 23:12:37

我正在尝试获取base64编码的字符串，并使用将其作为php中的图像返回。在第一行，如果我使用它，则返回错误，如果我是硬编码，则base64字符串而不是使用它，所有这些都有效并返回图像。我怎么能通过使用$_POST$_POST['imgdata']preg_match$_POST$_POST

工程

$imgstr = 'data:image/png;base64,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';

不起作用

$imgstr = $_POST['imgdata'];

完整代码

$imgstr = $_POST['imgdata'];   
// Grab the MIME type and the data with a regex for convenience
if (!preg_match('/data:([^;]*);base64,(.*)/', $imgstr, $matches)) {
    die("error");
}

// Decode the data
$content = base64_decode($matches[2]);

// Output the correct HTTP headers (may add more if you require them)
header('Content-Type: '.$matches[1]);
header('Content-Length: '.strlen($content));

// Output the actual image data
echo $content;

答案 1

如前所述，不应错过“+”，其余的都是直截了当的。使用 $_REQUEST 如果您不确定它是发布还是获取。

// requires php5
define('UPLOAD_DIR', 'images/');
$img = $_REQUEST['img'];
$img = str_replace('data:image/png;base64,', '', $img);
$img = str_replace(' ', '+', $img);
$data = base64_decode($img);
$file = UPLOAD_DIR . uniqid() . '.png';
$success = file_put_contents($file, $data);
print $success ? $file : 'Unable to save the file.';

答案 2

这是一个，你想以下吗？

<?php
$imgstr = 'image/png;base64,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';
$new_data=explode(";",$imgstr);
$type=$new_data[0];
$data=explode(",",$new_data[1]);
header("Content-type:".$type);
echo base64_decode($data[1]);
?>

上面的代码会按照您的意愿生成输出，试试这个这可能会对您有所帮助。

很抱歉延迟回复，现在只有我在很长一段时间后恢复我的StackOverFlow帐户

注意：忽略用于图像解码的PHP文件上开始的“”标记之前的空白区域，如果该文件上有任何空值，则表示它会抛出错误消息，并且在解码后不会创建或显示原始图像