我创建了一个类似的类,类似于休眠所建议的类,该类是可配置的,并且无需仅为此持久性创建新类型。
可以像这样使用
@Type(type = "ro.raisercostin.hibernate.EnumUserType", parameters = @Parameter(name = "type", value = "DealType"))
DealType dealType;
我添加了一个参数化类型的实现来支持传递的参数。
public class EnumUserType implements UserType, ParameterizedType {
private static final int[] SQL_TYPES = { Types.VARCHAR };
private Class clazz = null;
public EnumUserType() {
}
@Override
public void setParameterValues(Properties parameters) {
String className = (String) parameters.get("type");
try {
this.clazz = Class.forName(className);
} catch (ClassNotFoundException e) {
throw new RuntimeException("Couldn't get the class for name [" + className + "].", e);
}
}
public int[] sqlTypes() {
return SQL_TYPES;
}
public Class returnedClass() {
return clazz;
}
public Object nullSafeGet(ResultSet resultSet, String[] names, Object owner) throws HibernateException,
SQLException {
String name = resultSet.getString(names[0]);
Object result = null;
if (!resultSet.wasNull()) {
result = Enum.valueOf(clazz, name);
}
return result;
}
public void nullSafeSet(PreparedStatement preparedStatement, Object value, int index) throws HibernateException,
SQLException {
if (null == value) {
preparedStatement.setNull(index, Types.VARCHAR);
} else {
preparedStatement.setString(index, ((Enum) value).name());
}
}
public Object deepCopy(Object value) throws HibernateException {
return value;
}
public boolean isMutable() {
return false;
}
public Object assemble(Serializable cached, Object owner) throws HibernateException {
return cached;
}
public Serializable disassemble(Object value) throws HibernateException {
return (Serializable) value;
}
public Object replace(Object original, Object target, Object owner) throws HibernateException {
return original;
}
public int hashCode(Object x) throws HibernateException {
return x.hashCode();
}
public boolean equals(Object x, Object y) throws HibernateException {
if (x == y) {
return true;
}
if ((null == x) || (null == y)) {
return false;
}
return x.equals(y);
}
}