我需要Android中HttpClient的替代选项将数据发送到PHP，因为它不再受支持

我也遇到过这个问题，要解决，我已经做了自己的类。哪个基于 java.net，并支持Android的API 24，请查看：HttpRequest.java

使用此类，您可以轻松：

1. 发送 Http 请求GET
2. 发送 Http 请求POST
3. 发送 Http 请求PUT
4. 发送DELETE
5. 发送请求而无需额外的数据参数和检查响应HTTP status code
6. 将自定义添加到请求（使用 varargs）HTTP Headers
7. 将数据参数添加为查询以请求String
8. 将数据参数添加为 {key=value}HashMap
9. 接受响应为String
10. 接受响应为JSONObject
11. 接受响应为字节数组（对文件有用）byte []

以及这些的任意组合 - 只需一行代码）

以下是一些示例：

//Consider next request: 
HttpRequest req=new HttpRequest("http://host:port/path");

示例 1：

//prepare Http Post request and send to "http://host:port/path" with data params name=Bubu and age=29, return true - if worked
req.prepare(HttpRequest.Method.POST).withData("name=Bubu&age=29").send();

示例 2：

// prepare http get request,  send to "http://host:port/path" and read server's response as String 
req.prepare().sendAndReadString();

示例 3：

// prepare Http Post request and send to "http://host:port/path" with data params name=Bubu and age=29 and read server's response as JSONObject 
HashMap<String, String>params=new HashMap<>();
params.put("name", "Groot"); 
params.put("age", "29");
req.prepare(HttpRequest.Method.POST).withData(params).sendAndReadJSON();

示例 4：

//send Http Post request to "http://url.com/b.c" in background  using AsyncTask
new AsyncTask<Void, Void, String>(){
        protected String doInBackground(Void[] params) {
            String response="";
            try {
                response=new HttpRequest("http://url.com/b.c").prepare(HttpRequest.Method.POST).sendAndReadString();
            } catch (Exception e) {
                response=e.getMessage();
            }
            return response;
        }
        protected void onPostExecute(String result) {
            //do something with response
        }
    }.execute(); 

示例 5：

//Send Http PUT request to: "http://some.url" with request header:
String json="{\"name\":\"Deadpool\",\"age\":40}";//JSON that we need to send
String url="http://some.url";//URL address where we need to send it 
HttpRequest req=new HttpRequest(url);//HttpRequest to url: "http://some.url"
req.withHeaders("Content-Type: application/json");//add request header: "Content-Type: application/json"
req.prepare(HttpRequest.Method.PUT);//Set HttpRequest method as PUT
req.withData(json);//Add json data to request body
JSONObject res=req.sendAndReadJSON();//Accept response as JSONObject

示例 6：

//Equivalent to previous example, but in a shorter way (using methods chaining):
String json="{\"name\":\"Deadpool\",\"age\":40}";//JSON that we need to send
String url="http://some.url";//URL address where we need to send it 
//Shortcut for example 5 complex request sending & reading response in one (chained) line
JSONObject res=new HttpRequest(url).withHeaders("Content-Type: application/json").prepare(HttpRequest.Method.PUT).withData(json).sendAndReadJSON();

示例 7：

//Downloading file
byte [] file = new HttpRequest("http://some.file.url").prepare().sendAndReadBytes();
FileOutputStream fos = new FileOutputStream("smile.png");
fos.write(file);
fos.close();

HttpClient 已被弃用，现在已被删除：

org.apache.http.client.HttpClient:

此接口在 API 级别 22 中已弃用。请改用 openConnection（）。请访问此网页了解更多详情。

表示您应该切换到 。java.net.URL.openConnection()

另请参阅新的 HttpURLConnection 文档。

以下是您可以执行的操作：

URL url = new URL("http://some-server");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");

// read the response
System.out.println("Response Code: " + conn.getResponseCode());
InputStream in = new BufferedInputStream(conn.getInputStream());
String response = org.apache.commons.io.IOUtils.toString(in, "UTF-8");
System.out.println(response);

IOUtilsdocumentation： Apache Commons IO
Maven dependency： http://search.maven.org/#artifactdetails|org.apache.commons|commons-io|1.3.2|jarIOUtils