如何在安卓设备上使用 Cookie 发出 http 请求？

url cookies http android java

2022-08-31 08:42:39

我想在正确处理cookie的同时向远程服务器发出http请求（例如，存储服务器发送的cookie，并在我发出后续请求时发送这些cookie）。保留任何和所有cookie会很好，但实际上我唯一关心的是会话cookie。

对于 java.net，似乎首选方法是使用java.net.CookieHandler（抽象基类）和java.net.CookieManager（具体实现）。Android有java.net.CookieHandler，但它似乎没有java.net.CookieManager。

我可以通过检查http标头来手动编写所有代码，但似乎必须有更简单的方法。

在Android上发出http请求同时保留cookie的正确方法是什么？

答案 1

事实证明，Google Android附带了Apache HttpClient 4.0，并且我能够使用HttpClient文档中的“基于表单的登录”示例来弄清楚如何做到这一点：

https://github.com/apache/httpcomponents-client/blob/master/httpclient5/src/test/java/org/apache/hc/client5/http/examples/ClientFormLogin.java

import java.util.ArrayList;
import java.util.List;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.cookie.Cookie;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import org.apache.http.protocol.HTTP;

/**
 * A example that demonstrates how HttpClient APIs can be used to perform
 * form-based logon.
 */
public class ClientFormLogin {

    public static void main(String[] args) throws Exception {

        DefaultHttpClient httpclient = new DefaultHttpClient();

        HttpGet httpget = new HttpGet("https://portal.sun.com/portal/dt");

        HttpResponse response = httpclient.execute(httpget);
        HttpEntity entity = response.getEntity();

        System.out.println("Login form get: " + response.getStatusLine());
        if (entity != null) {
            entity.consumeContent();
        }
        System.out.println("Initial set of cookies:");
        List<Cookie> cookies = httpclient.getCookieStore().getCookies();
        if (cookies.isEmpty()) {
            System.out.println("None");
        } else {
            for (int i = 0; i < cookies.size(); i++) {
                System.out.println("- " + cookies.get(i).toString());
            }
        }

        HttpPost httpost = new HttpPost("https://portal.sun.com/amserver/UI/Login?" +
                "org=self_registered_users&" +
                "goto=/portal/dt&" +
                "gotoOnFail=/portal/dt?error=true");

        List <NameValuePair> nvps = new ArrayList <NameValuePair>();
        nvps.add(new BasicNameValuePair("IDToken1", "username"));
        nvps.add(new BasicNameValuePair("IDToken2", "password"));

        httpost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8));

        response = httpclient.execute(httpost);
        entity = response.getEntity();

        System.out.println("Login form get: " + response.getStatusLine());
        if (entity != null) {
            entity.consumeContent();
        }

        System.out.println("Post logon cookies:");
        cookies = httpclient.getCookieStore().getCookies();
        if (cookies.isEmpty()) {
            System.out.println("None");
        } else {
            for (int i = 0; i < cookies.size(); i++) {
                System.out.println("- " + cookies.get(i).toString());
            }
        }

        // When HttpClient instance is no longer needed, 
        // shut down the connection manager to ensure
        // immediate deallocation of all system resources
        httpclient.getConnectionManager().shutdown();        
    }
}

答案 2

Cookie 只是另一个 HTTP 标头。您始终可以在使用apache库或HTTPUrlConnection进行HTTP调用时设置它。无论哪种方式，您都应该能够以这种方式读取和设置HTTP Cookie。

您可以阅读本文以获取更多信息。

我可以分享我的代码和平，以演示您可以多么容易地制作它。

public static String getServerResponseByHttpGet(String url, String token) {

        try {
            HttpClient client = new DefaultHttpClient();
            HttpGet get = new HttpGet(url);
            get.setHeader("Cookie", "PHPSESSID=" + token + ";");
            Log.d(TAG, "Try to open => " + url);

            HttpResponse httpResponse = client.execute(get);
            int connectionStatusCode = httpResponse.getStatusLine().getStatusCode();
            Log.d(TAG, "Connection code: " + connectionStatusCode + " for request: " + url);

            HttpEntity entity = httpResponse.getEntity();
            String serverResponse = EntityUtils.toString(entity);
            Log.d(TAG, "Server response for request " + url + " => " + serverResponse);

            if(!isStatusOk(connectionStatusCode))
                return null;

            return serverResponse;

        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        } catch (IllegalArgumentException e) {
            e.printStackTrace();
        } catch (Exception e) {
            e.printStackTrace();
        }

        return null;
    }