Gson 序列化 POJO 的 ArrayList 的麻烦

2022-08-31 13:47:53

我一直计划使用simpleXML来满足我的序列化需求,但我想我会尝试JSON,以学习新的东西。

这是我用来尝试使用Gson 1.7.1序列化测试POJO的ArrayList的代码。

注意:我删除了字符串“s”的读取器/写入器以简化代码。

package test;

import java.io.IOException;
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;

import com.google.gson.Gson;

public class TestGsonSerialDeserialList {
    public static void main(String[] args) throws IOException{
        Gson gson = new Gson();

        //Make Serial 
        String s;
        List<TestObject> list = Collections.synchronizedList(new ArrayList<TestObject>() );
        list.add(new TestObject());
        list.add(new TestObject());

        s = gson.toJson(list, ArrayList.class);
        System.out.println(s);

        //Eat Serial
        List<TestObject> list2 = Collections.synchronizedList(gson.fromJson(s, ArrayList.class) );
        System.out.println(list2.get(0) );
        System.out.println(list2.get(1) );
    }
}

这是我得到的输出:

[{"objectID":1,"i1":12345,"name":"abcdefg","s":["a","b","c"]},{"objectID":2,"i1":12345,"name":"abcdefg","s":["a","b","c"]}]
java.lang.Object@5c74c3aa
java.lang.Object@75d9fd51

在我的新手眼中,这看起来是正确的。只是,反序列化的对象列表包含基本对象,而不是 TestObject 的 I 序列化。任何人都可以向我解释一下,如果有的话,我能做些什么来使这项工作发挥作用?

编辑:

更正为测试:感谢 ColinD

package test;

import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.Reader;
import java.io.Writer;
import java.lang.reflect.Type;
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;

import com.google.gson.Gson;
import com.google.gson.reflect.TypeToken;

public class TestGsonSerialDeserialList {
    public static void main(String[] args) throws IOException{
        System.out.println("--- Serialize / Deserialize Started ---");
        String fileName = "json\\testList.json";

        Gson gson = new Gson();
        Type listOfTestObject = new TypeToken<List<TestObject>>(){}.getType();

        //Make Serial 
        Writer osWriter = new OutputStreamWriter( new FileOutputStream(fileName));
        List<TestObject> list = Collections.synchronizedList(new ArrayList<TestObject>() );
        list.add(new TestObject());
        list.add(new TestObject());
        list.add(new TestObject());
        list.add(new TestObject());
        gson.toJson(list, osWriter);
        osWriter.close();


        //Eat Serial
        Reader isReader = new InputStreamReader( new FileInputStream((fileName) ) );
        List<TestObject> list2 = Collections.synchronizedList(
            (List<TestObject>)gson.fromJson(isReader, listOfTestObject) 
        );
        isReader.close();
        System.out.println(list2.get(0) );
        System.out.println(list2.get(1) );
        System.out.println(list2.get(2) );
        System.out.println(list2.get(3) );
        System.out.println("--- Serialize / Deserialize Ended ---");
    }
}

输出:

--- Serialize / Deserialize Started ---
ID#: 1, i1: 12345, name: abcdefg, s[]: [Ljava.lang.String;@95c083
ID#: 2, i1: 12345, name: abcdefg, s[]: [Ljava.lang.String;@6791d8c1
ID#: 3, i1: 12345, name: abcdefg, s[]: [Ljava.lang.String;@182d9c06
ID#: 4, i1: 12345, name: abcdefg, s[]: [Ljava.lang.String;@5a5e5a50
--- Serialize / Deserialize Ended ---

编辑2:

老实说,我不知道为什么,但是当我用ArrayList替换嵌入在TestObject中的简单String[]时,它开始正确序列化。

--- Serialize / Deserialize Started ---
ID#: 1, i1: 12345, name: abcdefg, s[]: [a, b, c]
ID#: 2, i1: 12345, name: abcdefg, s[]: [a, b, c]
ID#: 3, i1: 12345, name: abcdefg, s[]: [a, b, c]
ID#: 4, i1: 12345, name: abcdefg, s[]: [a, b, c]
--- Serialize / Deserialize Ended ---

答案 1

您需要向 Gson 提供有关您正在使用的特定泛型类型(或您与之一起使用的任何泛型类型)的信息。特别是在反序列化 JSON 时,它需要该信息才能确定应将每个数组元素反序列化为哪种类型的对象。List

Type listOfTestObject = new TypeToken<List<TestObject>>(){}.getType();
String s = gson.toJson(list, listOfTestObject);
List<TestObject> list2 = gson.fromJson(s, listOfTestObject);

这记录在 Gson 用户指南中。


答案 2