如何检查URL是否存在或返回Java的404?溶液
2022-08-31 13:08:54
String urlString = "http://www.nbc.com/Heroes/novels/downloads/Heroes_novel_001.pdf";
URL url = new URL(urlString);
if(/* Url does not return 404 */) {
System.out.println("exists");
} else {
System.out.println("does not exists");
}
urlString = "http://www.nbc.com/Heroes/novels/downloads/Heroes_novel_190.pdf";
url = new URL(urlString);
if(/* Url does not return 404 */) {
System.out.println("exists");
} else {
System.out.println("does not exists");
}
这应该打印
exists
does not exists
测试
public static String URL = "http://www.nbc.com/Heroes/novels/downloads/";
public static int getResponseCode(String urlString) throws MalformedURLException, IOException {
URL u = new URL(urlString);
HttpURLConnection huc = (HttpURLConnection) u.openConnection();
huc.setRequestMethod("GET");
huc.connect();
return huc.getResponseCode();
}
System.out.println(getResponseCode(URL + "Heroes_novel_001.pdf"));
System.out.println(getResponseCode(URL + "Heroes_novel_190.pdf"));
System.out.println(getResponseCode("http://www.example.com"));
System.out.println(getResponseCode("http://www.example.com/junk"));
输出
200
200
200
404
溶液
在 .connect() 之前添加下一行,输出将为 200、404、200、404
huc.setRequestProperty("User-Agent", "Mozilla/5.0 (Windows; U; Windows NT 6.0; en-US; rv:1.9.1.2) Gecko/20090729 Firefox/3.5.2 (.NET CLR 3.5.30729)");