在Java中将文件读入byte[]数组的优雅方式

2022-08-31 13:13:36

可能的重复:
Java 中的文件到字节 []

我想从文件中读取数据并将其取消到包裹。在文档中,不清楚FileInputStream是否有方法读取其所有内容。为了实现这一点,我做了以下操作:

FileInputStream filein = context.openFileInput(FILENAME);


int read = 0;
int offset = 0;
int chunk_size = 1024;
int total_size = 0;

ArrayList<byte[]> chunks = new ArrayList<byte[]>();
chunks.add(new byte[chunk_size]);
//first I read data from file chunk by chunk
while ( (read = filein.read(chunks.get(chunks.size()-1), offset, buffer_size)) != -1) {
    total_size+=read;
    if (read == buffer_size) {
         chunks.add(new byte[buffer_size]);
    }
}
int index = 0;

// then I create big buffer        
byte[] rawdata = new byte[total_size];

// then I copy data from every chunk in this buffer
for (byte [] chunk: chunks) {
    for (byte bt : chunk) {
         index += 0;
         rawdata[index] = bt;
         if (index >= total_size) break;
    }
    if (index>= total_size) break;
}

// and clear chunks array
chunks.clear();

// finally I can unmarshall this data to Parcel
Parcel parcel = Parcel.obtain();
parcel.unmarshall(rawdata,0,rawdata.length);

我认为这段代码看起来很丑陋,我的问题是:如何将数据从文件读取到byte[]中漂亮地?:)


答案 1

很久以前:

呼叫这些中的任何一个

byte[] org.apache.commons.io.FileUtils.readFileToByteArray(File file)
byte[] org.apache.commons.io.IOUtils.toByteArray(InputStream input) 

http://commons.apache.org/io/

如果库占用空间对于您的Android应用程序来说太大,您可以只使用commons-io库中的相关类

今天(Java 7+或Android API Level 26+)

幸运的是,我们现在在nio包中有几个方便的方法。例如:

byte[] java.nio.file.Files.readAllBytes(Path path)

Javadoc here


答案 2

这也将工作:

import java.io.*;

public class IOUtil {

    public static byte[] readFile(String file) throws IOException {
        return readFile(new File(file));
    }

    public static byte[] readFile(File file) throws IOException {
        // Open file
        RandomAccessFile f = new RandomAccessFile(file, "r");
        try {
            // Get and check length
            long longlength = f.length();
            int length = (int) longlength;
            if (length != longlength)
                throw new IOException("File size >= 2 GB");
            // Read file and return data
            byte[] data = new byte[length];
            f.readFully(data);
            return data;
        } finally {
            f.close();
        }
    }
}