使用 MongoDb 创建索引

2022-09-03 05:39:09

我是MongoDB的初学者,我正在尝试一些东西。我想存储URL并避免重复的URL,我在URL上创建了一个唯一的索引。诸如此类

collection.createIndex(new BasicDBObject("url", type).append("unique", true));

但是每次我启动我的程序时,索引都会再次创建,不是吗?

因为,现在我的程序只插入一个网址“http://site.com”,如果我重新启动我的程序,这个网址会再次插入,就像没有索引一样。

每次创建索引是处理索引的错误方法吗?

这是我的代码的一个示例

mongo.getCollection().ensureIndex(new BasicDBObject("url", 1).append("unique", "true"));

mongo.getCollection().insert(new BasicDBObject("url", "http://site.com").append("crawled", 0));

mongo.getCollection().insert(new BasicDBObject("url", "http://site.com").append("crawled", 0));

输出:

{ "_id" : { "$oid" : "50d627cf44ae5d6b5e9cf106"} , "url" : "http://site.com" , "crawled" : 0}
{ "_id" : { "$oid" : "50d627cf44ae5d6b5e9cf107"} , "url" : "http://site.com" , "crawled" : 0}

谢谢

编辑:

这是我的类Mongo,它处理MongoDB import java.net.UnknownHostException;import java.util.List;import java.util.Set;

import com.mongodb.BasicDBObject;import com.mongodb.DB;import com.mongodb.DBCollection;import com.mongodb.DBObject;import com.mongodb.MongoClient;

public class Mongo {

    private MongoClient mongoClient;
    private DB db;
    private DBCollection collection;
    private String db_name;

    public Mongo(String db){

        try {
            mongoClient = new MongoClient( "localhost" , 27017 );

            this.db = mongoClient.getDB(db);
            this.db_name = db;
        } catch (UnknownHostException e) {
            e.printStackTrace();
        }

    }

    public void drop(){
        mongoClient.dropDatabase(db_name);
    }

    public void listCollections(){
        Set<String> colls = db.getCollectionNames();

        for (String s : colls) {
            System.out.println(s);
        }
    }

    public void listIndex(){
         List<DBObject> list = collection.getIndexInfo();

            for (DBObject o : list) {
                System.out.println("\t" + o);
            }
    }

    public void setCollection(String col){
        this.collection = db.getCollection(col);
    }

    public void insert(BasicDBObject doc){

        this.collection.insert(doc);

    }

    public DBCollection getCollection(){
        return collection;
    }

    public void createIndex(String on, int type){
        collection.ensureIndex(new BasicDBObject(on, type).append("unique", true));
    }


}

这是我的类,它处理我的程序

public class Explorer {

    private final static boolean DEBUG = false;
    private final static boolean RESET = false;

    private Mongo mongo;

    private String host;

    public Explorer(String url){
        mongo = new Mongo("explorer");
        mongo.setCollection("page");

        if (RESET){
            mongo.drop();
            System.out.println("Set RESET to FALSE and restart the program.");
            System.exit(1);
        }

        if (DEBUG) {
            mongo.listCollections();

        }

        this.host = url.toLowerCase();



        BasicDBObject doc = new BasicDBObject("url", "http://site.com").append("crawled", 0);

        mongo.getCollection().ensureIndex(new BasicDBObject("url", 1).append("unique", true));

        mongo.getCollection().insert(new BasicDBObject("url", "http://site.com").append("crawled", 0));

        mongo.getCollection().insert(new BasicDBObject("url", "http://site.com").append("crawled", 0));




        process();
    }


    private void process(){


        BasicDBObject query = new BasicDBObject("crawled", 0);

        DBCursor cursor = mongo.getCollection().find(query);

        try {
            while(cursor.hasNext()) {
                System.out.println(cursor.next());
            }
        } finally {
            cursor.close();
        }

    }
}

答案 1

您需要将唯一值作为布尔值 true 传递,而不是作为字符串传递,这是选项的第二个参数:

...ensureIndex(new BasicDBObject("url", 1), new BasicDBObject("unique", true));

另外,我使用mongo解释器手动测试了它:

> db.createCollection("sa")
{ "ok" : 1 }
> db.sa.ensureIndex({"url":1},{unique:true})
> db.sa.insert({url:"http://www.example.com", crawled: true})
> db.sa.insert({url:"http://www.example.com", crawled: true})
E11000 duplicate key error index: test.sa.$url_1  dup key: { : "http://www.example.com" }
> db.sa.insert({url:"http://www.example2.com/", crawled: false})
> db.sa.insert({url:"http://www.example.com", crawled: false})
E11000 duplicate key error index: test.sa.$url_1  dup key: { : "http://www.example.com" }
>

只有两个对象:

> db.sa.find()
{ "_id" : ObjectId("50d636baa050939da1e4c53b"), "url" : "http://www.example.com", "crawled" : true }
{ "_id" : ObjectId("50d636dba050939da1e4c53d"), "url" : "http://www.example2.com/", "crawled" : false }

答案 2

我不完全理解你的问题,但我觉得你很可能应该使用而不是因为后者总是试图创建索引,而前者只会确保它的存在。ensureIndexcreateIndex