等待在MainSignalCatcherAndroid应用程序中出现错误

2022-09-03 07:06:41

我有一个Android应用程序,每33毫秒刷新一次屏幕,在一对坐标处显示一个矩形。下面是自定义视图的代码:

import android.content.Context;
import android.graphics.Bitmap;
import android.graphics.BitmapFactory;
import android.graphics.Canvas;
import android.os.Handler;
import android.util.AttributeSet;
import android.view.SurfaceHolder;
import android.view.SurfaceView;

public class OurView extends SurfaceView implements SurfaceHolder.Callback {

    private SurfaceHolder holder;
    private Handler handler = new Handler();
    private Bitmap testimg;
    private int xCoord = 500;
    private int yCoord = 500;
    boolean running = false;
    int xPos;
    int yPos;

    public OurView(Context context) {
        super(context);
        init();
    }

    public OurView(Context context, AttributeSet attrs) {
        super(context, attrs);
        init();
    }

    public OurView(Context context, AttributeSet attrs, int defStyle) {
        super(context, attrs, defStyle);
        init();
    }

    private void init() {
        holder = getHolder();
        holder.addCallback(this);
        testimg = BitmapFactory.decodeResource(getResources(),R.drawable.testimg);
    }

    void moveImage(int xChange, int yChange) {
        this.xCoord = this.xCoord + xChange;
        this.yCoord = this.yCoord + yChange;
    }

    void doDraw(Canvas canvas) {
        xPos = this.xCoord + (testimg.getWidth()/2);
        yPos = this.yCoord + (testimg.getHeight()/2);
        canvas.drawARGB(255, 55, 255, 255);
        canvas.drawBitmap(testimg, xPos, yPos, null);
    }

    @Override
    public void surfaceCreated(final SurfaceHolder holder) {
        running = true;
        while(running){

            handler.postDelayed(new Runnable() {
                public void run() {

                    Canvas canvas = getHolder().lockCanvas();

                    if(canvas != null){
                        synchronized (getHolder()) {
                            doDraw(canvas);
                        }
                        holder.unlockCanvasAndPost(canvas);
                    }

                }
            }, 33);

        }
    }

    @Override
    public void surfaceChanged(SurfaceHolder holder, int format, int width, int height) {}


    @Override
    public void surfaceDestroyed(SurfaceHolder holder) {}

}

我曾经有一个单独的线程来处理绘图,但这会导致线程之间具有不同值的变量出现问题。当我运行这个程序时,我得到这个错误:

04-20 10:54:35.577    1925-1931/com.thatoneprogrammerkid.gameminimum I/art﹕ Thread[2,tid=1931,WaitingInMainSignalCatcherLoop,Thread*=0xae668400,peer=0x12c00080,"Signal Catcher"]: reacting to signal 3
04-20 10:54:35.577    1925-1931/com.thatoneprogrammerkid.gameminimum I/art﹕ [ 04-20 10:54:35.627  1925: 1931 W/art      ]

答案 1

这不是错误,而是 VM 让你知道你的应用已发送信号 3 (SIGQUIT)。最可能的原因是应用无响应,系统正在执行 ANR 处理 - SIGQUIT 导致 VM 转储堆栈跟踪。

您是否在 logcat 中看到 ANR 投诉?

查看代码,你正在循环进入 ,该代码在 UI 线程上运行。这意味着你的应用将无法处理来自系统的消息(或利用视图,或接收用户输入)。您可以像以前一样使用单独的线程(但具有更好的同步),或者只是从中删除循环,然后让绘制处理程序在每次执行时重新发出。surfaceCreated()surfaceCreated()postDelayed()


答案 2

推荐