将响应发送到除发件人之外的所有客户端

javascript node.js socket.io

2022-08-30 00:29:44

要向所有客户端发送内容，请使用：

io.sockets.emit('response', data);

要从客户端接收，请使用：

socket.on('cursor', function(data) {
  ...
});

如何将两者结合起来，以便在从客户端接收服务器上的消息时，将该消息发送给除发送消息的用户之外的所有用户？

socket.on('cursor', function(data) {
  io.sockets.emit('response', data);
});

我是否必须通过发送带有消息的客户端ID，然后在客户端进行检查来破解它，还是有更简单的方法？

答案 1

这是我的列表（针对1.0进行了更新）：

// sending to sender-client only
socket.emit('message', "this is a test");

// sending to all clients, include sender
io.emit('message', "this is a test");

// sending to all clients except sender
socket.broadcast.emit('message', "this is a test");

// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');

// sending to all clients in 'game' room(channel), include sender
io.in('game').emit('message', 'cool game');

// sending to sender client, only if they are in 'game' room(channel)
socket.to('game').emit('message', 'enjoy the game');

// sending to all clients in namespace 'myNamespace', include sender
io.of('myNamespace').emit('message', 'gg');

// sending to individual socketid
socket.broadcast.to(socketid).emit('message', 'for your eyes only');

// list socketid
for (var socketid in io.sockets.sockets) {}
 OR
Object.keys(io.sockets.sockets).forEach((socketid) => {});

答案 2

从@LearnRPG答案，但使用1.0：

 // send to current request socket client
 socket.emit('message', "this is a test");

 // sending to all clients, include sender
 io.sockets.emit('message', "this is a test"); //still works
 //or
 io.emit('message', 'this is a test');

 // sending to all clients except sender
 socket.broadcast.emit('message', "this is a test");

 // sending to all clients in 'game' room(channel) except sender
 socket.broadcast.to('game').emit('message', 'nice game');

 // sending to all clients in 'game' room(channel), include sender
 // docs says "simply use to or in when broadcasting or emitting"
 io.in('game').emit('message', 'cool game');

 // sending to individual socketid, socketid is like a room
 socket.broadcast.to(socketid).emit('message', 'for your eyes only');

要回答@Crashalot评论，来自：socketid

var io = require('socket.io')(server);
io.on('connection', function(socket) { console.log(socket.id); })