看看这是否有效:
try {
if (subjectString.matches(
"(?ix)\\A(?: # Anchor address\n" +
" (?: # Mixed\n" +
" (?:[A-F0-9]{1,4}:){6} # Non-compressed\n" +
" |(?=(?:[A-F0-9]{0,4}:){2,6} # Compressed with 2 to 6 colons\n" +
" (?:[0-9]{1,3}\\.){3}[0-9]{1,3} # and 4 bytes\n" +
" \\z) # and anchored\n" +
" (([0-9A-F]{1,4}:){1,5}|:)((:[0-9A-F]{1,4}){1,5}:|:) # and at most 1 double colon\n" +
" |::(?:[A-F0-9]{1,4}:){5} # Compressed with 7 colons and 5 numbers\n" +
" )\n" +
" (?:(?:25[0-5]|2[0-4][0-9]|1[0-9][0-9]|[1-9]?[0-9])\\.){3} # 255.255.255.\n" +
" (?:25[0-5]|2[0-4][0-9]|1[0-9][0-9]|[1-9]?[0-9]) # 255\n" +
"| # Standard\n" +
" (?:[A-F0-9]{1,4}:){7}[A-F0-9]{1,4} # Standard\n" +
"| # Compressed\n" +
" (?=(?:[A-F0-9]{0,4}:){0,7}[A-F0-9]{0,4} # Compressed with at most 7 colons\n" +
" \\z) # and anchored\n" +
" (([0-9A-F]{1,4}:){1,7}|:)((:[0-9A-F]{1,4}){1,7}|:) # and at most 1 double colon\n" +
"|(?:[A-F0-9]{1,4}:){7}:|:(:[A-F0-9]{1,4}){7} # Compressed with 8 colons\n" +
")/[A-F0-9]{0,4}\\z # Anchor address"))
{
// String matched entirely
} else {
// Match attempt failed
}
} catch (PatternSyntaxException ex) {
// Syntax error in the regular expression
}
大约一年前,我购买了一个名为RegexMagic的非常有用的程序,用于我计划使用的一些复杂的正则表达式。
这被认为是Java,所以它应该编译,我假设/60可以在0000和FFFF的范围之间,你可以修改最后一部分。
/[A-F0-9]{0,4} 是我添加到正则表达式中以匹配您的示例的内容。