将 C# RSACryptoServiceProvider 转换为 JAVA 代码

security java c# encryption rsa

2022-09-04 02:51:46

我得到了这个由 Web 服务团队编写的 C# 代码，该代码公开了我计划使用的一些 Web 服务。我的密码需要使用此代码进行加密，以便 Web 服务知道如何在其端对其进行解密。

using(RSACryptoServiceProvider rsa = new RSACryptoServiceProvider())
{
    rsa.FromXmlString(publicKey);
    byte[] plainBytes = Encoding.Unicode.GetBytes(clearText);
    byte[] encryptedBytes = rsa.Encrypt(plainBytes, false);
    return Convert.ToBase64String(encryptedBytes);
}

我正在使用Java来使用此Web服务，现在，我在将#C代码转换为Java代码时遇到问题，因为该Web服务无法正确解密我的密码。

这是我目前失败的尝试：-

// my clear text password
String clearTextPassword = "XXXXX";

// these values are provided by the web service team
String modulusString = "...";
String publicExponentString = "...";

BigInteger modulus = new BigInteger(1, Base64.decodeBase64(modulusString.getBytes("UTF-8")));
BigInteger publicExponent = new BigInteger(1, Base64.decodeBase64(publicExponentString.getBytes("UTF-8")));

KeyFactory keyFactory = KeyFactory.getInstance("RSA");

RSAPublicKeySpec publicKeySpec = new RSAPublicKeySpec(modulus, publicExponent);
PublicKey publicKey = keyFactory.generatePublic(publicKeySpec);

Cipher cipher = Cipher.getInstance("RSA/ECB/NoPadding");
cipher.init(Cipher.ENCRYPT_MODE, publicKey);

String encodedEncryptedPassword = new String(Base64.encodeBase64(cipher.doFinal(clearTextPassword.getBytes("UTF-8"))));

我做错了什么？非常感谢。

2013-08-07 - 更新

我正在阅读这个网站，我意识到我的模量值和公共指数值不在十六进制中。因此，我稍微修改了我的代码，并尝试了@Dev中提到的代码。RSA/ECB/PKCS1PADDING

// my clear text password
String clearTextPassword = "XXXXX";

// these are the actual values I get from the web service team
String modulusString = "hm2oRCtP6usJKYpq7o1K20uUuL11j5xRrbV4FCQhn/JeXLT21laKK9901P69YUS3bLo64x8G1PkCfRtjbbZCIaa1Ci/BCQX8nF2kZVfrPyzcmeAkq4wsDthuZ+jPInknzUI3TQPAzdj6gim97E731i6WP0MHFqW6ODeQ6Dsp8pc=";
String publicExponentString = "AQAB";

Base64 base64Encoder = new Base64();

String modulusHex = new String(Hex.encodeHex(modulusString.getBytes("UTF-8")));
String publicExponentHex = new String(Hex.encodeHex(publicExponentString.getBytes("UTF-8")));

BigInteger modulus = new BigInteger(modulusHex, 16);
BigInteger publicExponent = new BigInteger(publicExponentHex);

KeyFactory keyFactory = KeyFactory.getInstance("RSA");

RSAPublicKeySpec publicKeySpec = new RSAPublicKeySpec(modulus, publicExponent);
PublicKey publicKey = keyFactory.generatePublic(publicKeySpec);

Cipher cipher = Cipher.getInstance("RSA/ECB/PKCS1PADDING");
cipher.init(Cipher.ENCRYPT_MODE, publicKey);

String encodedEncryptedPassword = new String(base64Encoder.encode(cipher.doFinal(clearTextPassword.getBytes("UTF-8"))));

当我点击Web服务时，我收到此错误：“要解密的数据超过了此128字节模数的最大值。似乎明文密码仍未正确加密。

任何帮助或建议都非常感谢。谢谢。

2013-08-09 - 解决方案

我在下面发布了我的最终工作解决方案。

答案 1

找到解决方案。

String modulusString = "hm2oRCtP6usJKYpq7o1K20uUuL11j5xRrbV4FCQhn/JeXLT21laKK9901P69YUS3bLo64x8G1PkCfRtjbbZCIaa1Ci/BCQX8nF2kZVfrPyzcmeAkq4wsDthuZ+jPInknzUI3TQPAzdj6gim97E731i6WP0MHFqW6ODeQ6Dsp8pc=";
String publicExponentString = "AQAB";

byte[] modulusBytes = Base64.decodeBase64(modulusString);
byte[] exponentBytes = Base64.decodeBase64(publicExponentString);
BigInteger modulus = new BigInteger(1, modulusBytes);
BigInteger publicExponent = new BigInteger(1, exponentBytes);

RSAPublicKeySpec rsaPubKey = new RSAPublicKeySpec(modulus, publicExponent);
KeyFactory fact = KeyFactory.getInstance("RSA");
PublicKey pubKey = fact.generatePublic(rsaPubKey);
Cipher cipher = Cipher.getInstance("RSA/ECB/PKCS1PADDING");
cipher.init(Cipher.ENCRYPT_MODE, pubKey);

byte[] plainBytes = clearTextPassword.getBytes("UTF-16LE");
byte[] cipherData = cipher.doFinal(plainBytes);
String encryptedStringBase64 = Base64.encodeBase64String(cipherData);

答案 2

根据RSACryptoServiceProvider.Encrypt上的MSDN文档，当第二个参数是密码时，使用PKCS#1 v1.5填充。因此，您的密码规范不正确。false

请尝试。RSA/ECB/PKCS1PADDING

您正在将密钥材料转换为第二个代码示例中的很多内容，并且您破坏了它，最终使您的密码认为您拥有的密钥材料比实际拥有的要多，并使消息太长（这会触发您的错误）以及另一端的解密密码无法理解。直接转换为字节数组，并将其传递给。BigInteger

String modulusString = "...";
String publicExponentString = "...";

byte[] mod = Base64.decodeBase64(modulusString);
byte[] e = Base64.decodeBase64(publicExponentString);

BigInteger modulus = new BigInteger(1, mod);
BigInteger publicExponent = new BigInteger(1, e);