mongodb mongoTemplate使用一些标准获得不同的字段
2022-09-04 08:14:54
My MongoDB json structure 是
{
"_id" : "122134231234234",
"name" : "Total_pop",
"description" : "sales category",
"source" : "public",
"dataset" :"d1"
},
{
"_id" : "1123421231234234",
"name" : "Total_pop",
"description" : "sales category",
"source" : "public",
"dataset" :"d1"
},
{
"_id" : "12312342332423343",
"name" : "Total_pop",
"description" : "sales category",
"source" : "private",
"description" : "d1"
}
我需要获取与源是公共的数据集不同的集合。我尝试了这个查询,但它不起作用:
Criteria criteria = new Criteria();
criteria.where("source").in("public");
query.addCriteria(criteria);
query.fields().include("name");
query.fields().include("description");
query.fields().include("description");
query.fields().include("source"); List list =
mongoTemplate.getCollection("collectionname").distinct("source", query);
你能帮帮我吗?