对 XML 文件的 HTTP 请求

2022-09-04 19:28:04

我正在尝试在Android上使用Flurry Analytics作为我的程序,但我无法从服务器获取xml文件本身。

我正在接近,因为在Log Cat System.out标签中,由于某种原因,我可以得到它的一半,它说“XML传递异常= java.net.MalformedURLException:协议未找到:?xml版本= 1.0编码=”UTF-8“等...直到我的xml代码大约一半。不确定我做错了什么,我正在发送一个HTTP get,标头请求接受应用程序/ xml,但它无法正常工作。任何帮助是值得赞赏的!

try {

                //HttpResponse response = client.execute(post);
                //HttpEntity r_entity = response.getEntity();
                //String xmlString = EntityUtils.toString(r_entity);

        HttpClient client = new DefaultHttpClient();  
        String URL = "http://api.flurry.com/eventMetrics/Event?apiAccessCode=????&apiKey=??????&startDate=2011-2-28&endDate=2011-3-1&eventName=Tip%20Calculated";
        HttpGet get = new HttpGet(URL);
        get.addHeader("Accept", "application/xml");
        get.addHeader("Content-Type", "application/xml");
        HttpResponse responsePost = client.execute(get);  
        HttpEntity resEntity = responsePost.getEntity(); 
        if (resEntity != null) 

        {  
                    System.out.println("Not null!");

                    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();

                    DocumentBuilder db = dbf.newDocumentBuilder();

                    String responseXml = EntityUtils.toString(responsePost.getEntity());
                    Document doc = db.parse(responseXml);
                    doc.getDocumentElement().normalize();

                    NodeList nodeList = doc.getElementsByTagName("eventMetrics");


                    for (int i = 0; i < nodeList.getLength(); i++)
                    {
                        Node node = nodeList.item(i);   

                        Element fstElmnt = (Element) node;

                        NodeList nameList = fstElmnt.getElementsByTagName("day");

                        Element dayElement = (Element) nameList.item(0);

                        nameList = dayElement.getChildNodes();

                        countString = dayElement.getAttribute("totalCount");
                        System.out.println(countString);
                        count = Integer.parseInt(countString);
                        System.out.println(count);
                        count += count;

                    }
        }

    } catch (Exception e) {

                    System.out.println("XML Passing Exception = " + e);

                }

答案 1

采用字符串的解析方法适用于 URL 格式。在解析字符串之前,您需要将字符串包装在字符串阅读器中。如果您可以获取XML作为输入流并解析它,那就更好了,如下所示:

String uri =
    "http://api.flurry.com/eventMetrics/Event?apiAccessCode=?????&apiKey=??????&startDate=2011-2-28&endDate=2011-3-1&eventName=Tip%20Calculated";

URL url = new URL(uri);
HttpURLConnection connection =
    (HttpURLConnection) url.openConnection();
connection.setRequestMethod("GET");
connection.setRequestProperty("Accept", "application/xml");

InputStream xml = connection.getInputStream();

DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(xml);

答案 2

我使用了HttpURLConnection,这是一个工作代码。

URL url = new URL("....");
HttpURLConnection httpConnection = (HttpURLConnection) url.openConnection();

httpConnection.setRequestMethod("POST");
httpConnection.setRequestProperty("Accept", "application/xml");
httpConnection.setRequestProperty("Content-Type", "application/xml");

httpConnection.setDoOutput(true);
OutputStream outStream = httpConnection.getOutputStream();
OutputStreamWriter outStreamWriter = new OutputStreamWriter(outStream, "UTF-8");
outStreamWriter.write(requestedXml);
outStreamWriter.flush();
outStreamWriter.close();
outStream.close();

System.out.println(httpConnection.getResponseCode());
System.out.println(httpConnection.getResponseMessage());

InputStream xml = httpConnection.getInputStream();

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