如何仅对具有特定属性集的元素使用 querySelectorAll？

你可以像这样使用：querySelectorAll()

var test = document.querySelectorAll('input[value][type="checkbox"]:not([value=""])');

这意味着：

获取属性“value”的所有输入，并且属性“value”不为空。

在此演示中，它将禁用具有非空值的复选框。

以您的示例为例：

<input type="checkbox" id="c2" name="c2" value="DE039230952"/>

将 $$ 替换为 document.querySelectorAll，在以下示例中为：

$$('input') //Every input
$$('[id]') //Every element with id
$$('[id="c2"]') //Every element with id="c2"
$$('input,[id]') //Every input + every element with id
$$('input[id]') //Every input including id
$$('input[id="c2"]') //Every input including id="c2"
$$('input#c2') //Every input including id="c2" (same as above)
$$('input#c2[value="DE039230952"]') //Every input including id="c2" and value="DE039230952"
$$('input#c2[value^="DE039"]') //Every input including id="c2" and value has content starting with DE039
$$('input#c2[value$="0952"]') //Every input including id="c2" and value has content ending with 0952
$$('input#c2[value*="39230"]') //Every input including id="c2" and value has content including 39230

直接使用上面的示例，无需额外的库，只需添加：

const $$ = document.querySelectorAll.bind(document);

一些补充：

$$(.) //The same as $([class])
$$(div > input) //div is parent tag to input
document.querySelector() //equals to $$()[0] or $()