如何在特定坐标中定位DIV？

将其和属性分别脚本化为距左边缘和上边缘的像素数。它必须具有lefttopposition: absolute;

var d = document.getElementById('yourDivId');
d.style.position = "absolute";
d.style.left = x_pos+'px';
d.style.top = y_pos+'px';

或者将其作为一个函数来执行，以便您可以将其附加到诸如此类的事件中onmousedown

function placeDiv(x_pos, y_pos) {
  var d = document.getElementById('yourDivId');
  d.style.position = "absolute";
  d.style.left = x_pos+'px';
  d.style.top = y_pos+'px';
}

您不必使用Javascript来执行此操作。使用普通的旧css：

div.blah {
  position:absolute;
  top: 0; /*[wherever you want it]*/
  left:0; /*[wherever you want it]*/
}

如果你觉得你必须使用javascript，或者正在尝试使用JQuery动态地做到这一点，这会影响类“blah”的所有div：

var blahclass =  $('.blah'); 
blahclass.css('position', 'absolute');
blahclass.css('top', 0); //or wherever you want it
blahclass.css('left', 0); //or wherever you want it

或者，如果你必须使用常规的旧javascript，你可以通过id抓取

var domElement = document.getElementById('myElement');// don't go to to DOM every time you need it. Instead store in a variable and manipulate.
domElement.style.position = "absolute";
domElement.style.top = 0; //or whatever 
domElement.style.left = 0; // or whatever