PHP：合并两个数组，同时保留键而不是重新索引？

php arrays array-merge

2022-08-30 06:06:56

如何在保留字符串/int 键的同时合并两个数组（一个包含字符串 = > 值对，另一个具有 int => 值对）？它们都不会重叠（因为一个只有字符串，另一个只有整数）。

这是我当前的代码（这不起作用，因为array_merge正在使用整数键重新索引数组）：

// get all id vars by combining the static and dynamic
$staticIdentifications = array(
 Users::userID => "USERID",
 Users::username => "USERNAME"
);
// get the dynamic vars, formatted: varID => varName
$companyVarIdentifications = CompanyVars::getIdentificationVarsFriendly($_SESSION['companyID']);
// merge the static and dynamic vars (*** BUT KEEP THE INT INDICES ***)
$idVars = array_merge($staticIdentifications, $companyVarIdentifications);

答案 1

您可以简单地“添加”数组：

>> $a = array(1, 2, 3);
array (
  0 => 1,
  1 => 2,
  2 => 3,
)
>> $b = array("a" => 1, "b" => 2, "c" => 3)
array (
  'a' => 1,
  'b' => 2,
  'c' => 3,
)
>> $a + $b
array (
  0 => 1,
  1 => 2,
  2 => 3,
  'a' => 1,
  'b' => 2,
  'c' => 3,
)

答案 2

考虑到您有

$replaced = array('1' => 'value1', '4' => 'value4');
$replacement = array('4' => 'value2', '6' => 'value3');

执行将输出：$merge = $replacement + $replaced;

Array('4' => 'value2', '6' => 'value3', '1' => 'value1');

sum 中的第一个数组将在最终输出中具有值。

执行将输出：$merge = $replaced + $replacement;

Array('1' => 'value1', '4' => 'value4', '6' => 'value3');