从 PHP 脚本返回 JSON

虽然没有它通常很好，但你可以并且应该设置标题：Content-Type

<?php
$data = /** whatever you're serializing **/;
header('Content-Type: application/json; charset=utf-8');
echo json_encode($data);

如果我不使用特定的框架，我通常允许一些请求参数修改输出行为。它通常可用于快速故障排除，不发送标头，或者有时数据有效负载来吸引它（尽管在大多数情况下，它不应该是必需的）。print_r

返回JSON的完整清晰的PHP代码是：

$option = $_GET['option'];

if ( $option == 1 ) {
    $data = [ 'a', 'b', 'c' ];
    // will encode to JSON array: ["a","b","c"]
    // accessed as example in JavaScript like: result[1] (returns "b")
} else {
    $data = [ 'name' => 'God', 'age' => -1 ];
    // will encode to JSON object: {"name":"God","age":-1}  
    // accessed as example in JavaScript like: result.name or result['name'] (returns "God")
}

header('Content-type: application/json');
echo json_encode( $data );