如何使用 PHP 发送 POST 请求？

php post http request

2022-08-30 05:47:24

实际上，我想在搜索查询完成后阅读搜索查询之后的内容。问题是URL只接受方法，并且不对方法进行任何操作...POSTGET

我必须在或的帮助下阅读所有内容。有没有什么方法可以让我用方法发送参数，然后通过？domdocumentfile_get_contents()POSTPHP

答案 1

PHP5 的无 CURL 方法：

$url = 'http://server.com/path';
$data = array('key1' => 'value1', 'key2' => 'value2');

// use key 'http' even if you send the request to https://...
$options = array(
    'http' => array(
        'header'  => "Content-type: application/x-www-form-urlencoded\r\n",
        'method'  => 'POST',
        'content' => http_build_query($data)
    )
);
$context  = stream_context_create($options);
$result = file_get_contents($url, false, $context);
if ($result === FALSE) { /* Handle error */ }

var_dump($result);

有关该方法以及如何添加标头的更多信息，请参阅 PHP 手册，例如：

stream_context_create： http://php.net/manual/en/function.stream-context-create.php

答案 2

您可以使用 cURL：

<?php
//The url you wish to send the POST request to
$url = $file_name;

//The data you want to send via POST
$fields = [
    '__VIEWSTATE '      => $state,
    '__EVENTVALIDATION' => $valid,
    'btnSubmit'         => 'Submit'
];

//url-ify the data for the POST
$fields_string = http_build_query($fields);

//open connection
$ch = curl_init();

//set the url, number of POST vars, POST data
curl_setopt($ch,CURLOPT_URL, $url);
curl_setopt($ch,CURLOPT_POST, true);
curl_setopt($ch,CURLOPT_POSTFIELDS, $fields_string);

//So that curl_exec returns the contents of the cURL; rather than echoing it
curl_setopt($ch,CURLOPT_RETURNTRANSFER, true); 

//execute post
$result = curl_exec($ch);
echo $result;
?>