PHP 如何查找自日期时间以来经过的时间？

大多数答案似乎都集中在将日期从字符串转换为时间上。似乎您主要考虑将日期设置为“5天前”格式，等等。右？

这就是我这样做的方式：

$time = strtotime('2010-04-28 17:25:43');

echo 'event happened '.humanTiming($time).' ago';

function humanTiming ($time)
{

    $time = time() - $time; // to get the time since that moment
    $time = ($time<1)? 1 : $time;
    $tokens = array (
        31536000 => 'year',
        2592000 => 'month',
        604800 => 'week',
        86400 => 'day',
        3600 => 'hour',
        60 => 'minute',
        1 => 'second'
    );

    foreach ($tokens as $unit => $text) {
        if ($time < $unit) continue;
        $numberOfUnits = floor($time / $unit);
        return $numberOfUnits.' '.$text.(($numberOfUnits>1)?'s':'');
    }

}

我还没有测试过，但它应该有效。

结果将如下所示

event happened 4 days ago

或

event happened 1 minute ago

干杯

想要分享php函数，导致语法正确的Facebook，如人类可读的时间格式。

例：

echo get_time_ago(strtotime('now'));

结果：

1分钟前

function get_time_ago($time_stamp)
{
    $time_difference = strtotime('now') - $time_stamp;

    if ($time_difference >= 60 * 60 * 24 * 365.242199)
    {
        /*
         * 60 seconds/minute * 60 minutes/hour * 24 hours/day * 365.242199 days/year
         * This means that the time difference is 1 year or more
         */
        return get_time_ago_string($time_stamp, 60 * 60 * 24 * 365.242199, 'year');
    }
    elseif ($time_difference >= 60 * 60 * 24 * 30.4368499)
    {
        /*
         * 60 seconds/minute * 60 minutes/hour * 24 hours/day * 30.4368499 days/month
         * This means that the time difference is 1 month or more
         */
        return get_time_ago_string($time_stamp, 60 * 60 * 24 * 30.4368499, 'month');
    }
    elseif ($time_difference >= 60 * 60 * 24 * 7)
    {
        /*
         * 60 seconds/minute * 60 minutes/hour * 24 hours/day * 7 days/week
         * This means that the time difference is 1 week or more
         */
        return get_time_ago_string($time_stamp, 60 * 60 * 24 * 7, 'week');
    }
    elseif ($time_difference >= 60 * 60 * 24)
    {
        /*
         * 60 seconds/minute * 60 minutes/hour * 24 hours/day
         * This means that the time difference is 1 day or more
         */
        return get_time_ago_string($time_stamp, 60 * 60 * 24, 'day');
    }
    elseif ($time_difference >= 60 * 60)
    {
        /*
         * 60 seconds/minute * 60 minutes/hour
         * This means that the time difference is 1 hour or more
         */
        return get_time_ago_string($time_stamp, 60 * 60, 'hour');
    }
    else
    {
        /*
         * 60 seconds/minute
         * This means that the time difference is a matter of minutes
         */
        return get_time_ago_string($time_stamp, 60, 'minute');
    }
}

function get_time_ago_string($time_stamp, $divisor, $time_unit)
{
    $time_difference = strtotime("now") - $time_stamp;
    $time_units      = floor($time_difference / $divisor);

    settype($time_units, 'string');

    if ($time_units === '0')
    {
        return 'less than 1 ' . $time_unit . ' ago';
    }
    elseif ($time_units === '1')
    {
        return '1 ' . $time_unit . ' ago';
    }
    else
    {
        /*
         * More than "1" $time_unit. This is the "plural" message.
         */
        // TODO: This pluralizes the time unit, which is done by adding "s" at the end; this will not work for i18n!
        return $time_units . ' ' . $time_unit . 's ago';
    }
}