如何从访问者那里获得真正的IP？

php ip

2022-08-30 07:27:07

我正在使用此PHP代码来获取访问者的IP地址：

<?php echo $_SERVER['REMOTE_ADDR']; ?>

但是，当访问者使用代理时，我无法从他们那里获取真正的IP地址。在这种情况下，有没有办法获取访问者的IP地址？

答案 1

试试这个php代码。

<?PHP

function getUserIP()
{
    // Get real visitor IP behind CloudFlare network
    if (isset($_SERVER["HTTP_CF_CONNECTING_IP"])) {
              $_SERVER['REMOTE_ADDR'] = $_SERVER["HTTP_CF_CONNECTING_IP"];
              $_SERVER['HTTP_CLIENT_IP'] = $_SERVER["HTTP_CF_CONNECTING_IP"];
    }
    $client  = @$_SERVER['HTTP_CLIENT_IP'];
    $forward = @$_SERVER['HTTP_X_FORWARDED_FOR'];
    $remote  = $_SERVER['REMOTE_ADDR'];

    if(filter_var($client, FILTER_VALIDATE_IP))
    {
        $ip = $client;
    }
    elseif(filter_var($forward, FILTER_VALIDATE_IP))
    {
        $ip = $forward;
    }
    else
    {
        $ip = $remote;
    }

    return $ip;
}


$user_ip = getUserIP();

echo $user_ip; // Output IP address [Ex: 177.87.193.134]


?>

答案 2

这是我见过的最常见的技术：

function getUserIP() {
    if( array_key_exists('HTTP_X_FORWARDED_FOR', $_SERVER) && !empty($_SERVER['HTTP_X_FORWARDED_FOR']) ) {
        if (strpos($_SERVER['HTTP_X_FORWARDED_FOR'], ',')>0) {
            $addr = explode(",",$_SERVER['HTTP_X_FORWARDED_FOR']);
            return trim($addr[0]);
        } else {
            return $_SERVER['HTTP_X_FORWARDED_FOR'];
        }
    }
    else {
        return $_SERVER['REMOTE_ADDR'];
    }
}

请注意，它并不能保证您将始终获得正确的用户IP，因为有很多方法可以隐藏它。