PHP 函数，用于删除字符串中某些字符之间的所有字符

php string

2022-08-30 13:13:08

我感兴趣的是，这将在给定$string中搜索$char 1和$char 2，如果发现这种情况，可以从这两个字符之间的子字符串中清除$string，包括$char 1和$char 2本身。function delete_all_between($char1, $char2, $string)

例：

$string = 'Some valid and <script>some invalid</script> text!';
delete_all_between('<script>', '</script>', $string);

现在，$string应该只包含

'Some valid and  text'; //note two spaces between 'and  text'

有人有快速的解决方案吗？

答案 1

<?php

$string = 'Some valid and <script>some invalid</script> text!';
$out = delete_all_between('<script>', '</script>', $string);
print($out);

function delete_all_between($beginning, $end, $string) {
  $beginningPos = strpos($string, $beginning);
  $endPos = strpos($string, $end);
  if ($beginningPos === false || $endPos === false) {
    return $string;
  }

  $textToDelete = substr($string, $beginningPos, ($endPos + strlen($end)) - $beginningPos);

  return delete_all_between($beginning, $end, str_replace($textToDelete, '', $string)); // recursion to ensure all occurrences are replaced
}

答案 2

下面是一个单行线：

preg_replace('/START[\s\S]+?END/', '', $string);

替换和:)学分转到另一个SO线程！STARTEND