PHP 条带标点符号

php regex

2022-08-30 13:50:44

假设我有这个：

$hello = "Hello, is StackOverflow a helpful website!? Yes!";

我想去掉标点符号，这样它就会输出为：

hello_is_stackoverflow_a_helpful_website_yes

我该怎么做？

答案 1

# to keep letters & numbers
$s = preg_replace('/[^a-z0-9]+/i', '_', $s); # or...
$s = preg_replace('/[^a-z\d]+/i', '_', $s);

# to keep letters only
$s = preg_replace('/[^a-z]+/i', '_', $s); 

# to keep letters, numbers & underscore
$s = preg_replace('/[^\w]+/', '_', $s);

# same as third example; suggested by @tchrist; ^\w = \W
$s = preg_replace('/\W+/', '_', $s);

对于字符串

$s = "Hello, is StackOverflow a helpful website!? Yes!";

结果（对于所有示例）为

Hello_is_StackOverflow_a_helpful_website_Yes_

享受！

答案 2

function strip_punctuation($string) {
    $string = strtolower($string);
    $string = preg_replace("/[:punct:]+/", "", $string);
    $string = str_replace(" +", "_", $string);
    return $string;
}

首先将字符串转换为小写，然后删除标点符号，然后用下划线替换空格（这将处理一个或多个空格，因此如果有人放置两个空格，它将仅替换为一个下划线）。