JavaScript 中数组交集的最简单代码
2022-08-29 22:14:52
在javascript中实现数组交集的最简单,无库的代码是什么?我想写
intersection([1,2,3], [2,3,4,5])
并获取
[2, 3]
在javascript中实现数组交集的最简单,无库的代码是什么?我想写
intersection([1,2,3], [2,3,4,5])
并获取
[2, 3]
使用 Array.prototype.filter
和 Array.prototype.include 的组合
:
const filteredArray = array1.filter(value => array2.includes(value));
对于较旧的浏览器,使用Array.prototype.indexOf
并且没有箭头函数:
var filteredArray = array1.filter(function(n) {
return array2.indexOf(n) !== -1;
});
铌!两者都通过使用 在内部比较数组中的元素,因此如果数组包含对象,它将仅比较对象引用(而不是其内容)。如果要指定自己的比较逻辑,请改用 Array.prototype.some
。.includes
.indexOf
===
破坏性似乎是最简单的,特别是如果我们可以假设输入是排序的:
/* destructively finds the intersection of
* two arrays in a simple fashion.
*
* PARAMS
* a - first array, must already be sorted
* b - second array, must already be sorted
*
* NOTES
* State of input arrays is undefined when
* the function returns. They should be
* (prolly) be dumped.
*
* Should have O(n) operations, where n is
* n = MIN(a.length, b.length)
*/
function intersection_destructive(a, b)
{
var result = [];
while( a.length > 0 && b.length > 0 )
{
if (a[0] < b[0] ){ a.shift(); }
else if (a[0] > b[0] ){ b.shift(); }
else /* they're equal */
{
result.push(a.shift());
b.shift();
}
}
return result;
}
非破坏性必须更复杂,因为我们必须跟踪索引:
/* finds the intersection of
* two arrays in a simple fashion.
*
* PARAMS
* a - first array, must already be sorted
* b - second array, must already be sorted
*
* NOTES
*
* Should have O(n) operations, where n is
* n = MIN(a.length(), b.length())
*/
function intersect_safe(a, b)
{
var ai=0, bi=0;
var result = [];
while( ai < a.length && bi < b.length )
{
if (a[ai] < b[bi] ){ ai++; }
else if (a[ai] > b[bi] ){ bi++; }
else /* they're equal */
{
result.push(a[ai]);
ai++;
bi++;
}
}
return result;
}