如何在PHP中获取当前页面的Google +1计数？

php google-api google-plus-one api google-plus

2022-08-30 21:44:16

我想获得当前网页的谷歌+1s计数？我想在PHP中执行此过程，然后将共享数或+1写入数据库。这就是为什么，我需要它。那么，我如何在PHP中执行此过程（获得+1s的计数）？
提前致谢。

答案 1

这个对我有用，比CURL更快：

function getPlus1($url) {
    $html =  file_get_contents( "https://plusone.google.com/_/+1/fastbutton?url=".urlencode($url));
    $doc = new DOMDocument();   $doc->loadHTML($html);
    $counter=$doc->getElementById('aggregateCount');
    return $counter->nodeValue;
}

也在这里为推文，Pin图和脸书

function getTweets($url){
    $json = file_get_contents( "http://urls.api.twitter.com/1/urls/count.json?url=".$url );
    $ajsn = json_decode($json, true);
    $cont = $ajsn['count'];
    return $cont;
}

function getPins($url){
    $json = file_get_contents( "http://api.pinterest.com/v1/urls/count.json?callback=receiveCount&url=".$url );
    $json = substr( $json, 13, -1);
    $ajsn = json_decode($json, true);
    $cont = $ajsn['count'];
    return $cont;
}

function getFacebooks($url) { 
    $xml = file_get_contents("http://api.facebook.com/restserver.php?method=links.getStats&urls=".urlencode($url));
    $xml = simplexml_load_string($xml);
    $shares = $xml->link_stat->share_count;
    $likes  = $xml->link_stat->like_count;
    $comments = $xml->link_stat->comment_count; 
    return $likes + $shares + $comments;
}

注意：Facebook数字是喜欢+分享的总和，有些人说加上评论（我还没有搜索这个），无论如何使用你需要的那个。

如果您的php设置允许打开外部URL，请检查您的“allow_url_open”php设置，这将起作用。

希望有所帮助。

答案 2

function get_plusones($url) {
  $curl = curl_init();
  curl_setopt($curl, CURLOPT_URL, "https://clients6.google.com/rpc");
  curl_setopt($curl, CURLOPT_POST, 1);
  curl_setopt($curl, CURLOPT_POSTFIELDS, '[{"method":"pos.plusones.get","id":"p","params":{"nolog":true,"id":"' . $url . '","source":"widget","userId":"@viewer","groupId":"@self"},"jsonrpc":"2.0","key":"p","apiVersion":"v1"}]');
  curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
  curl_setopt($curl, CURLOPT_HTTPHEADER, array('Content-type: application/json'));
  $curl_results = curl_exec ($curl);
  curl_close ($curl);
  $json = json_decode($curl_results, true);
  return intval( $json[0]['result']['metadata']['globalCounts']['count'] );
}

echo get_plusones("http://www.stackoverflow.com")

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