php mysql Group By 获取最新记录，而不是第一条记录

php mysql

2022-08-30 21:48:43

表格：

(`post_id`, `forum_id`, `topic_id`, `post_time`) 
(79, 8, 4, '2012-11-19 06:58:08');
(80, 3, 3, '2012-11-19 06:58:42'),
(81, 9, 9, '2012-11-19 06:59:04'),
(82, 11, 6, '2012-11-19 16:05:39'),
(83, 9, 9, '2012-11-19 16:07:46'),
(84, 9, 11, '2012-11-19 16:09:33'),

查询：

SELECT  post_id, forum_id, topic_id FROM posts 
GROUP BY topic_id 
ORDER BY post_time DESC
LIMIT 5

结果：

[0] => [post_id] => 84 [forum_id] => 9 [topic_id] => 11  
[1] => [post_id] => 82 [forum_id] => 11 [topic_id] => 6  
[2] => [post_id] => 81 [forum_id] => 9 [topic_id] => 9  
[3] => [post_id] => 80 [forum_id] => 3 [topic_id] => 3  
[4] => [post_id] => 79 [forum_id] => 8 [topic_id] => 4

问题：

如何重写查询，使其返回post_id -> 83 而不是 post_id -> 81？

它们都具有相同的论坛和主题 ID，但 post_id -> 81 的日期比 post_id -> 83 更早。

但似乎Group By获得了“第一张”记录，而不是“最新”记录。

我尝试将查询更改为

SELECT  post_id, forum_id, topic_id, MAX(post_time)

但这同时返回post_id 81 和 83

答案 1

如果选择的特性未在 group 子句中使用，并且不是聚合，则结果未指定。也就是说，您不知道从哪些行中选择其他属性。（sql标准不允许这样的查询，但MySQL更宽松）。

然后，应将查询编写为例如

SELECT post_id, forum_id, topic_id
FROM posts p
WHERE post_time =
  (SELECT max(post_time) FROM posts p2
   WHERE p2.topic_id = p.topic_id
   AND p2.forum_id = p.forum_id)
GROUP BY forum_id, topic_id, post_id
ORDER BY post_time DESC
LIMIT 5;

或

SELECT post_id, forum_id, topic_id FROM posts
NATURAL JOIN
(SELECT forum_id, topic_id, max(post_time) AS post_time
 FROM posts
 GROUP BY forum_id, topic_id) p
ORDER BY post_time
LIMIT 5;

答案 2

它不是很漂亮，但它的工作原理：

SELECT * FROM (SELECT  post_id, forum_id, topic_id FROM posts
ORDER BY post_time DESC) as temp
GROUP BY topic_id