通过 PHP SDK 2 从 S3 抓取对象的内容?

2022-08-30 22:00:08

我一直在尝试弄清楚如何从S3存储桶中获取内容以包含在S3上的客户端的ZipArchive中,他们现在需要创建报告来保存客户推送到S3的文件。我尝试了PHP SDK 2 API(与PEAR一起安装)的以下内容:

require 'AWSSDKforPHP/aws.phar';

use Aws\S3\S3Client;
use Aws\Common\Enum\Region;

$config = array(
    'key'    => 'the-aws-key',
    'secret' => 'the-aws-secret',
    'region' => Region::US_EAST_1
);

$aws_s3 = S3Client::factory($config);
$app_config['s3']['bucket'] = 'the-aws-bucket';
$app_config['s3']['prefix'] = '';
$attach_name = 'hosted-test-file.jpg';
try {
    $result = $aws_s3->getObject(
        array(
            'Bucket' => $app_config['s3']['bucket'],
            'Key' => $app_config['s3']['prefix'].$attach_name
        )
    );
    var_dump($result);
    $body = $result->get('Body');
    var_dump($body);
    $handle = fopen('php://temp', 'r');
    $content = stream_get_contents($handle);
    echo "String length: ".strlen($content);
} catch(Aws\S3\Exception\S3Exception $e) {
    echo "Request failed.<br />";
}

但是,它返回的只是一个对象,不知道如何抓取实际内容,以便我可以将其推送到zip文件中。Guzzle\Http\EntityBody

抓取对象

object(Guzzle\Service\Resource\Model)[126]
    protected 'structure' => object(Guzzle\Service\Description\Parameter)[109]
    protected 'name' => null
    protected 'description' => null
    protected 'type' => string 'object' (length = 6)
    protected 'required' => boolean false
    protected 'enum' => null
    protected 'additionalProperties' => boolean true
    protected 'items' => null
    protected 'parent' => null
    protected 'ref' => null
    protected 'format' => null
    protected 'data' => array (size = 11)
        'Body' => object(Guzzle\Http\EntityBody)[97]
            protected 'contentEncoding' => boolean false
            protected 'rewindFunction' => null
            protected 'stream' => resource(292, stream)
            protected 'size' => int 3078337
            protected 'cache' => array (size = 9)
            ...
        'DeleteMarker' => string '' (length = 0)
        'Expiration' => string '' (length = 0)
        'WebsiteRedirectLocation' => string '' (length = 0)
        'LastModified' => string 'Fri, 30 Nov 2012 21:07:30 GMT' (length = 29)
        'ContentType' => string 'binary/octet-stream' (length = 19)
        'ContentLength' => string '3078337' (length = 7)
        'ETag' => string '"the-etag-of-the-file"' (length = 34)
        'ServerSideEncryption' => string '' (length = 0)
        'VersionId' => string '' (length = 0)
        'RequestId' => string 'request-id' (length = 16)

从正文返回

object(Guzzle\Http\EntityBody)[96]
    protected 'contentEncoding' => boolean false
    protected 'rewindFunction' => null
    protected 'stream' => resource(292, stream)
    protected 'size' => int 3078337
    protected 'cache' => array (size = 9)
        'wrapper_type' => string 'php' (length = 3)
        'stream_type' => string 'temp' (length = 4)
        'mode' => string 'w+b' (length = 3)
        'unread_bytes' => int 0
        'seekable' => boolean true
        'uri' => string 'php://temp' (length = 10)
        'is_local' => boolean true
        'is_readable' => boolean true
        'is_writable' => boolean true

// Echo of strlen()
String length: 0

任何信息将不胜感激,谢谢!

溶液

我花了一段时间来弄清楚,但我能够找到一个要点,为我指出正确的方向,为了获得文件的内容,你需要执行以下操作:

require 'AWSSDKforPHP/aws.phar';

use Aws\S3\S3Client;
use Aws\Common\Enum\Region;

$config = array(
    'key'    => 'the-aws-key',
    'secret' => 'the-aws-secret',
    'region' => Region::US_EAST_1
);

$aws_s3 = S3Client::factory($config);
$app_config['s3']['bucket'] = 'the-aws-bucket';
$app_config['s3']['prefix'] = '';
$attach_name = 'hosted-test-file.jpg';
try {
    $result = $aws_s3->getObject(
        array(
            'Bucket' => $app_config['s3']['bucket'],
            'Key' => $app_config['s3']['prefix'].$attach_name
        )
    );
    $body = $result->get('Body');
    $body->rewind();
    $content = $body->read($result['ContentLength']);
} catch(Aws\S3\Exception\S3Exception $e) {
    echo "Request failed.<br />";
}

答案 1

响应的主体存储在对象中。这用于防止应用程序下载非常大的文件和内存不足。Guzzle\Http\EntityBody

如果需要将 EntityBody 对象的内容用作字符串,则可以将该对象强制转换为字符串:

$result = $s3Client->getObject(array(
    'Bucket' => $bucket,
    'Key'    => $key
));

// Cast as a string
$bodyAsString = (string) $result['Body'];

// or call __toString directly
$bodyAsString = $result['Body']->__toString();

如果需要,您还可以直接下载到目标文件:

use Guzzle\Http\EntityBody;

$s3Client->getObject(array(
  'Bucket' => $bucket,
  'Key'    => $key,
  'command.response_body' => EntityBody::factory(fopen("/tmp/{$key}", 'w+'))
));

答案 2

这对我有用:

$tempSave = 'path/to/save/filename.txt';

return $this->S3->getObject([
     'Bucket' => 'test',
     'Key'    => $keyName,
     'SaveAs' => $tempSave,
]);

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