HttpClient 中的 Authorization Bearer token?

我正在尝试使用Java中的oauth2授权令牌访问API 这是客户端代码

DefaultHttpClient httpclient = new DefaultHttpClient(); 
HttpPost post = new HttpPost("http://res-api");
post.setHeader("Content-Type","application/json");
post.setHeader("Authorization", "Bearer " + finalToken);

JSONObject json = new JSONObject();
// json.put ...
// Send it as request body in the post request 

StringEntity params = new StringEntity(json.toString());
post.setEntity(params);

HttpResponse response = httpclient.execute(post);
httpclient.getConnectionManager().shutdown();

这将返回 401。

等效的 curl 命令在相同的令牌下没有问题:

curl -H "Content-Type:application/json" -H "Authorization:Bearer randomToken" -X POST -d @example.json http://rest-api

我尝试注销请求,看起来授权设置正确

DEBUG [2016-06-28 20:51:13,655] org.apache.http.headers: >> Authorization: Bearer authRandomToKen; Path=/; Domain=oauth2-server; Expires=Wed, 29 Jun 2016 20:51:13 UTC

我通过复制粘贴相同的令牌尝试了curl命令,并且t工作正常

虽然我也看到这条线

DEBUG [2016-06-28 20:51:13,658] org.apache.http.impl.client.DefaultHttpClient: Response contains no authentication challenges

答案 1

我遇到过类似的情况,我能够通过以下方式做到这一点,我希望这将有助于其他人。

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;

public class HttpURLConnectionExample {


    public static void main(String[] args) throws Exception {

        // Sending get request
        URL url = new URL("http://example-url");
        HttpURLConnection conn = (HttpURLConnection) url.openConnection();

        conn.setRequestProperty("Authorization","Bearer "+" Actual bearer token issued by provider.");
        //e.g. bearer token= eyJhbGciOiXXXzUxMiJ9.eyJzdWIiOiPyc2hhcm1hQHBsdW1zbGljZS5jb206OjE6OjkwIiwiZXhwIjoxNTM3MzQyNTIxLCJpYXQiOjE1MzY3Mzc3MjF9.O33zP2l_0eDNfcqSQz29jUGJC-_THYsXllrmkFnk85dNRbAw66dyEKBP5dVcFUuNTA8zhA83kk3Y41_qZYx43T

        conn.setRequestProperty("Content-Type","application/json");
        conn.setRequestMethod("GET");


        BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream()));
        String output;

        StringBuffer response = new StringBuffer();
        while ((output = in.readLine()) != null) {
            response.append(output);
        }

        in.close();
        // printing result from response
        System.out.println("Response:-" + response.toString());

    }
}

答案 2

我试图使用HttpClient做类似的事情,我通过进行如下小的更改来使其工作。

post.setHeader(HttpHeaders.CONTENT_TYPE,"application/json");
post.setHeader(HttpHeaders.AUTHORIZATION, "Bearer " + finalToken);

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