如何在Selenium WebDriver中使用xPath来抓取SVG元素？

selenium svg xpath css-selectors java

2022-09-01 22:35:43

我正在测试一个基于的API，使用Selenium（Java版本）。OpenLayersWebDriver

我想测试使用 .控制.修改功能。我想单击绘制的要素（SVG），然后拖动并检查它们是否存在、可见还是隐藏。OpenLayers

我画了一个多边形，并且选择了它。请参阅下图：

polygon_and_handles

这些 SVG 元素的 HTML 如下：

<svg id="OpenLayers_Layer_Vector_161_svgRoot" width="1235" height="495" viewBox="0 0 1235 495" style="display: block;">
    <g id="OpenLayers_Layer_Vector_161_root" transform="" style="visibility: visible;">
        <g id="OpenLayers_Layer_Vector_161_vroot">
            <path id="OpenLayers_Geometry_Polygon_200" d=" M 393.0000000000964,213.9999999999891 486.0000000003338,275.9999999997126 384.00000000036925,284.9999999994434 393.0000000000964,213.9999999999891 z" fill-rule="evenodd" fill="blue" fill-opacity="0.4" stroke="blue" stroke-opacity="1" stroke-width="2" stroke-linecap="round" stroke-linejoin="round" stroke-dasharray="none" pointer-events="visiblePainted" cursor="pointer" />
            <circle id="OpenLayers_Geometry_Point_619" cx="439.50000000021464" cy="244.99999999985084" r="6" fill="#009900" fill-opacity="0.5" stroke="#ee9900" stroke-opacity="1" stroke-width="1" stroke-linecap="round" stroke-linejoin="round" stroke-dasharray="none" pointer-events="visiblePainted" cursor="inherit" />
            <circle id="OpenLayers_Geometry_Point_621" cx="435.00000000035106" cy="280.49999999958163" r="6" fill="#009900" fill-opacity="0.5" stroke="#ee9900" stroke-opacity="1" stroke-width="1" stroke-linecap="round" stroke-linejoin="round" stroke-dasharray="none" pointer-events="visiblePainted" cursor="inherit" />
            <circle id="OpenLayers_Geometry_Point_623" cx="388.50000000023283" cy="249.4999999997126" r="6" fill="#009900" fill-opacity="0.5" stroke="#ee9900" stroke-opacity="1" stroke-width="1" stroke-linecap="round" stroke-linejoin="round" stroke-dasharray="none" pointer-events="visiblePainted" cursor="inherit" />
            <circle id="OpenLayers_Geometry_Point_202" cx="393.0000000000964" cy="213.9999999999891" r="6" fill="#990000" fill-opacity="1" stroke="#ee9900" stroke-opacity="1" stroke-width="1" stroke-linecap="round" stroke-linejoin="round" stroke-dasharray="none" pointer-events="visiblePainted" cursor="inherit" />
            <circle id="OpenLayers_Geometry_Point_203" cx="486.0000000003338" cy="275.9999999997126" r="6" fill="#990000" fill-opacity="1" stroke="#ee9900" stroke-opacity="1" stroke-width="1" stroke-linecap="round" stroke-linejoin="round" stroke-dasharray="none" pointer-events="visiblePainted" cursor="inherit" />
            <circle id="OpenLayers_Geometry_Point_204" cx="384.00000000036925" cy="284.9999999994434" r="6" fill="#990000" fill-opacity="1" stroke="#ee9900" stroke-opacity="1" stroke-width="1" stroke-linecap="round" stroke-linejoin="round" stroke-dasharray="none" pointer-events="visiblePainted" cursor="inherit" />
        </g>
        <g id="OpenLayers_Layer_Vector_161_troot" />
    </g>
</svg>

假设我想选择红点。

我试过了：

String xpath = "//circle[contains(@id, 'OpenLayers_Geometry_Point') AND fill = '#990000']";
List<WebElement> vertices = driver.findElements(By.xpath(xpath));

但它总是返回一个空列表。[]

我在这里做错了什么？任何人都可以帮我吗？

多谢。

编辑 1 - 功能：顶点可见

在单击操作之前，我想获取元素并检查它们是否可见。我正在使用这个函数。

public static boolean verticesAreVisible(WebDriver driver, String xpath) {
    List<WebElement> list = driver.findElements(By.xpath(xpath));
    if (list.isEmpty()) {
        return false;
    }
    boolean visible = true;
    for (int i = 0; i < list.size(); i++) {
        visible = visible && list.get(i).isDisplayed();
    }
    return !verticesAreNotVisible(driver) && visible;
}

编辑 2 - 更正 x 路径

// This solution from Razib is valid if the SVG is on the root node
String xpath = "/*[name()='svg']/*[name()='circle']";
// I changed it so that any descendant is valid "//"
String xpath = "//*[name()='svg']//*[name()='circle']";
// Since I wanted only the red vertices, I added this
String xpath = "//*[name()='svg']//*[name()='circle' and @fill='#990000']";

答案 1

可能是您需要使用中的“操作与”属性。在您的 XPath 中使用它 -nameXpath

"/*[name()='svg']/*[name()='SVG OBJECT']"

然后尝试以下代码片段 -

WebElement svgObj = driver.findElement(By.xpath(XPATH));
Actions actionBuilder = new Actions(driver);
actionBuilder.click(svgObj).build().perform();

答案 2

要定位红点，即具有属性和 id 属性的元素包含OpenLayers_Geometry_Point可以使用以下任一定位器策略：fill="#990000"

使用 xpath：

//*[name()='svg']/*[name()='g']/*[name()='g']//*[name()='circle' and contains(@fill, '990000')][starts-with(@id, 'OpenLayers_Geometry_Point')]

使用 css 选择器：

svg > g > g circle[fill$='990000'][id^='OpenLayers_Geometry_Point']

理想情况下，您需要诱导 WebDriverWait for 和，并且可以使用以下任一定位器策略：visibilityOfAllElementsLocatedBy()

使用 cssSelector：

List<WebElement> vertices = new WebDriverWait(driver, 20).until(ExpectedConditions.visibilityOfAllElementsLocatedBy(By.cssSelector("svg > g > g circle[fill$='990000'][id^='OpenLayers_Geometry_Point']")));

使用 xpath：

List<WebElement> vertices = new WebDriverWait(driver, 20).until(ExpectedConditions.visibilityOfAllElementsLocatedBy(By.xpath("//*[name()='svg']/*[name()='g']/*[name()='g']//*[name()='circle' and contains(@fill, '990000')][starts-with(@id, 'OpenLayers_Geometry_Point')]")));

引用

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