您走在正确的轨道上。现在,您只需要提取所需的组,如下所示:
final Pattern pattern = Pattern.compile("<tag>(.+?)</tag>", Pattern.DOTALL);
final Matcher matcher = pattern.matcher("<tag>String I want to extract</tag>");
matcher.find();
System.out.println(matcher.group(1)); // Prints String I want to extract
如果要提取多个匹配项,请尝试以下操作:
public static void main(String[] args) {
final String str = "<tag>apple</tag><b>hello</b><tag>orange</tag><tag>pear</tag>";
System.out.println(Arrays.toString(getTagValues(str).toArray())); // Prints [apple, orange, pear]
}
private static final Pattern TAG_REGEX = Pattern.compile("<tag>(.+?)</tag>", Pattern.DOTALL);
private static List<String> getTagValues(final String str) {
final List<String> tagValues = new ArrayList<String>();
final Matcher matcher = TAG_REGEX.matcher(str);
while (matcher.find()) {
tagValues.add(matcher.group(1));
}
return tagValues;
}
但是,我同意正则表达式不是这里的最佳答案。我会使用XPath来查找我感兴趣的元素。有关详细信息,请参阅 Java XPath API。