如何 Ping 外部 IP 从 Java Android

android java

2022-08-31 15:53:36

我正在为Android 2.2开发一个Ping应用程序。

我尝试我的代码，它的工作原理，但仅在本地IP中，这是我的问题，我也想对外部服务器执行ping。

这是我的代码：

  private OnClickListener milistener = new OnClickListener() {
    public void onClick(View v) {
        TextView info = (TextView) findViewById(R.id.info);
        EditText edit = (EditText) findViewById(R.id.edit);
        Editable host = edit.getText();
        InetAddress in;
        in = null;
        // Definimos la ip de la cual haremos el ping
        try {
            in = InetAddress.getByName(host.toString());
        } catch (UnknownHostException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        // Definimos un tiempo en el cual ha de responder
        try {
            if (in.isReachable(5000)) {
                info.setText("Responde OK");
            } else {
                info.setText("No responde: Time out");
            }
        } catch (IOException e) {
            // TODO Auto-generated catch block
            info.setText(e.toString());
        }
    }
};

Ping 127.0.0.1 -> OK
Ping 8.8.8.8 （谷歌 DNS） -> 超时

我也在清单XML上放了以下行：

<uses-permission android:name="android.permission.INTERNET"></uses-permission>

任何人都可以建议我做错的地方吗？

答案 1

我尝试了以下代码，这对我有用。

private boolean executeCommand(){
        System.out.println("executeCommand");
        Runtime runtime = Runtime.getRuntime();
        try
        {
            Process  mIpAddrProcess = runtime.exec("/system/bin/ping -c 1 8.8.8.8");
            int mExitValue = mIpAddrProcess.waitFor();
            System.out.println(" mExitValue "+mExitValue);
            if(mExitValue==0){
                return true;
            }else{
                return false;
            }
        }
        catch (InterruptedException ignore)
        {
            ignore.printStackTrace();
            System.out.println(" Exception:"+ignore);
        } 
        catch (IOException e) 
        {
            e.printStackTrace();
            System.out.println(" Exception:"+e);
        }
        return false;
    }

答案 2

这是我在其中一个项目中使用的简单ping：

public static class Ping {
    public String net = "NO_CONNECTION";
    public String host = "";
    public String ip = "";
    public int dns = Integer.MAX_VALUE;
    public int cnt = Integer.MAX_VALUE;
}

public static Ping ping(URL url, Context ctx) {
    Ping r = new Ping();
    if (isNetworkConnected(ctx)) {
        r.net = getNetworkType(ctx);
        try {
            String hostAddress;
            long start = System.currentTimeMillis();
            hostAddress = InetAddress.getByName(url.getHost()).getHostAddress();
            long dnsResolved = System.currentTimeMillis();
            Socket socket = new Socket(hostAddress, url.getPort());
            socket.close();
            long probeFinish = System.currentTimeMillis();
            r.dns = (int) (dnsResolved - start);
            r.cnt = (int) (probeFinish - dnsResolved);
            r.host = url.getHost();
            r.ip = hostAddress;
        }
        catch (Exception ex) {
            Timber.e("Unable to ping");
        }
    }
    return r;
}

public static boolean isNetworkConnected(Context context) {
    ConnectivityManager cm =
            (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
    return activeNetwork != null && activeNetwork.isConnectedOrConnecting();
}

@Nullable
public static String getNetworkType(Context context) {
    ConnectivityManager cm =
            (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE);
    NetworkInfo activeNetwork = cm.getActiveNetworkInfo();
    if (activeNetwork != null) {
        return activeNetwork.getTypeName();
    }
    return null;
}

用法：ping(new URL("https://www.google.com:443/"), this);

结果：{"cnt":100,"dns":109,"host":"www.google.com","ip":"212.188.10.114","net":"WIFI"}