春季 MVC + JSON = 406 不可接受

2022-08-31 20:07:47

我正在尝试生成一个简单的JSON响应。现在我得到406不可接受的错误。Tomcat说:“此请求标识的资源只能根据请求”接受“标头生成具有不可接受的特征的响应。Accept

Accept:text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8

在tomcat/lib中,我有所有的Tomcat jars,Spring jars和jackson-all-1.9.0.jar。我正在使用Spring 3.2.2和Tomcat 7。

我知道这个问题已经讨论过很多次了,但没有一个解决方案对我有用。

网.xml

<web-app id="WebApp_ID" version="2.4" 
    xmlns="http://java.sun.com/xml/ns/j2ee" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
    http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

  <display-name>Spring Web MVC Application</display-name>

  <servlet>
    <servlet-name>dispatcher</servlet-name>
        <servlet-class>
                  org.springframework.web.servlet.DispatcherServlet
        </servlet-class>
        <load-on-startup>1</load-on-startup>
  </servlet>

  <servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
        <url-pattern>*.htm</url-pattern>
  </servlet-mapping>

</web-app>

调度程序-servlet.xml

<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:mvc="http://www.springframework.org/schema/mvc" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans 
    http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
     http://www.springframework.org/schema/context 
        http://www.springframework.org/schema/context/spring-context-3.0.xsd
        http://www.springframework.org/schema/mvc
        http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd">

    <bean id="viewResolver"
        class="org.springframework.web.servlet.view.InternalResourceViewResolver" >
        <property name="prefix">
            <value>/WEB-INF/pages/</value>
        </property>
        <property name="suffix">
            <value>.jsp</value>
        </property>
    </bean>
 <context:component-scan base-package="com.smiechmateusz.controller" />
 <context:annotation-config />

    <mvc:annotation-driven />

</beans>

你好世界控制器.java

package com.smiechmateusz.controller;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.AbstractController;

import com.smiechmateusz.dao.Foo;

@Controller
@RequestMapping("/")
public class HelloWorldController extends AbstractController{

    @Override
    protected ModelAndView handleRequestInternal(HttpServletRequest request,
        HttpServletResponse response) throws Exception {

        ModelAndView model = new ModelAndView("HelloWorldPage");
        return model;
    }

    @RequestMapping(value="foobar.htm", method = RequestMethod.GET)
    public @ResponseBody Foo getShopInJSON() {
        Foo f = new Foo();
        f.setX(1);
        f.setY(2);
        f.setDescription("desc");
        return f;
    }
}

傅.java

package com.smiechmateusz.dao;

import java.io.Serializable;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Table(name="foobaz")
public class Foo implements Serializable
{
    private int x, y;
    String description;
    int id;

    @Column(name = "x")
    public int getX() {
        return x;
    }
    public void setX(int x) {
        this.x = x;
    }
    @Column(name = "y")
    public int getY() {
        return y;
    }
    public void setY(int y) {
        this.y = y;
    }
    @Column(name = "description")
    public String getDescription() {
        return description;
    }
    public void setDescription(String description) {
        this.description = description;
    }

    @Id @GeneratedValue
    @Column(name = "id")
    public int getId() {
        return id;
    }
    public void setId(int id) {
        this.id = id;
    }
}

我已经尝试过添加

<bean id="jsonConverter" class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"></bean>
<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
        <property name="messageConverters">
          <list>
            <ref bean="jsonConverter"/>
          </list>
    </property>
</bean>

到我的调度程序-servlet.xml或者将jakcson-all更改为jackson-asljackson-core-asl,但输出是相同的。


答案 1

如果您使用的是 Maven 和最新的 Jackson 代码,则可以从 spring 配置 XML 文件中删除所有特定于 Jackson 的配置(您仍然需要一个注释驱动的标记<mvc:annotation-driven/>),只需将一些 Jackson 依赖项添加到 pom.xml 文件中即可。有关依赖项的示例,请参阅下文。这对我有用,我正在使用:

  • Apache Maven 3.0.4 (r1232337; 2012-01-17 01:44:56-0700)
  • org.springframework 版本 3.1.2.RELEASE
  • 弹簧安全版本3.1.0.发布。

    ...<dependencies>
    ...
        <dependency>
            <groupId>com.fasterxml.jackson.core</groupId>
            <artifactId>jackson-core</artifactId>
            <version>2.2.3</version>
        </dependency>
        <dependency>
            <groupId>com.fasterxml.jackson.core</groupId>
            <artifactId>jackson-databind</artifactId>
            <version>2.2.3</version>
        </dependency>
        <dependency>
            <groupId>com.fasterxml.jackson.core</groupId>
            <artifactId>jackson-annotations</artifactId>
            <version>2.2.3</version>
        </dependency>
        ...
    </dependencies>...
    

答案 2

获取此错误的另一种方法是创建一个没有公共成员的类。在这种情况下,406不可接受是一个非常无用的错误消息。