在Java中使用startsWith和endsWith时,如何忽略大小写?
2022-08-31 22:22:00
这是我的代码:
public static void rightSel(Scanner scanner,char t)
{
/*if (!stopping)*/System.out.print(": ");
if (scanner.hasNextLine())
{
String orInput = scanner.nextLine;
if (orInput.equalsIgnoreCase("help")
{
System.out.println("The following commands are available:");
System.out.println(" 'help' : displays this menu");
System.out.println(" 'stop' : stops the program");
System.out.println(" 'topleft' : makes right triangle alligned left and to the top");
System.out.println(" 'topright' : makes right triangle alligned right and to the top");
System.out.println(" 'botright' : makes right triangle alligned right and to the bottom");
System.out.println(" 'botleft' : makes right triangle alligned left and to the bottom");
System.out.println("To continue, enter one of the above commands.");
}//help menu
else if (orInput.equalsIgnoreCase("stop")
{
System.out.println("Stopping the program...");
stopping = true;
}//stop command
else
{
String rawInput = orInput;
String cutInput = rawInput.trim();
if (
我想让用户在如何输入命令方面留出一些余地,例如:右上角,右上角,右上角,左上角等。为此,我试图在最后检查是否以“top”或“up”开头,并检查是否以“left”或“right”结尾,同时不区分大小写。这有可能吗?if (
cutInput
cutInput
这样做的最终目标是允许用户在一行输入中从三角形的四个方向之一中进行选择。这是我能想到的最好的方法,但我对编程还很陌生,可能会让事情变得过于复杂。如果我是,并且有更简单的方法,请让我知道。