如何在渲染前获取文本视图的行数?

2022-09-01 00:58:16

我如何获得字符串在呈现之前将在a中占用的行数。TextView

A 将不起作用,因为只有在渲染后才会触发这些操作。ViewTreeObserver


答案 1

当整个单词放在下一行以避免中断该单词时,接受的答案不起作用:

|hello   |
|world!  |

100% 确定行数的唯一方法是使用与 TextView 相同的文本流引擎。由于TextView不共享其重排逻辑,因此这里有一个自定义字符串处理器,它将文本拆分为多行,每行都适合给定的宽度。它也尽力不打断单词,除非整个单词不适合:

public List<String> splitWordsIntoStringsThatFit(String source, float maxWidthPx, Paint paint) {
    ArrayList<String> result = new ArrayList<>();

    ArrayList<String> currentLine = new ArrayList<>();

    String[] sources = source.split("\\s");
    for(String chunk : sources) {
        if(paint.measureText(chunk) < maxWidthPx) {
            processFitChunk(maxWidthPx, paint, result, currentLine, chunk);
        } else {
            //the chunk is too big, split it.
            List<String> splitChunk = splitIntoStringsThatFit(chunk, maxWidthPx, paint);
            for(String chunkChunk : splitChunk) {
                processFitChunk(maxWidthPx, paint, result, currentLine, chunkChunk);
            }
        }
    }

    if(! currentLine.isEmpty()) {
        result.add(TextUtils.join(" ", currentLine));
    }
    return result;
}

/**
 * Splits a string to multiple strings each of which does not exceed the width
 * of maxWidthPx.
 */
private List<String> splitIntoStringsThatFit(String source, float maxWidthPx, Paint paint) {
    if(TextUtils.isEmpty(source) || paint.measureText(source) <= maxWidthPx) {
        return Arrays.asList(source);
    }

    ArrayList<String> result = new ArrayList<>();
    int start = 0;
    for(int i = 1; i <= source.length(); i++) {
        String substr = source.substring(start, i);
        if(paint.measureText(substr) >= maxWidthPx) {
            //this one doesn't fit, take the previous one which fits
            String fits = source.substring(start, i - 1);
            result.add(fits);
            start = i - 1;
        }
        if (i == source.length()) {
            String fits = source.substring(start, i);
            result.add(fits);
        }
    }

    return result;
}

/**
 * Processes the chunk which does not exceed maxWidth.
 */
private void processFitChunk(float maxWidth, Paint paint, ArrayList<String> result, ArrayList<String> currentLine, String chunk) {
    currentLine.add(chunk);
    String currentLineStr = TextUtils.join(" ", currentLine);
    if (paint.measureText(currentLineStr) >= maxWidth) {
        //remove chunk
        currentLine.remove(currentLine.size() - 1);
        result.add(TextUtils.join(" ", currentLine));
        currentLine.clear();
        //ok because chunk fits
        currentLine.add(chunk);
    }
}

下面是单元测试的一部分:

    String text = "Hello this is a very long and meanless chunk: abcdefghijkonetuhosnahrc.pgraoneuhnotehurc.pgansohtunsaohtu. Hope you like it!";
    Paint paint = new Paint();
    paint.setTextSize(30);
    paint.setTypeface(Typeface.DEFAULT_BOLD);

    List<String> strings = splitWordsIntoStringsThatFit(text, 50, paint);
    assertEquals(3, strings.size());
    assertEquals("Hello this is a very long and meanless chunk:", strings.get(0));
    assertEquals("abcdefghijkonetuhosnahrc.pgraoneuhnotehurc.pganso", strings.get(1));
    assertEquals("htunsaohtu. Hope you like it!", strings.get(2));

现在,人们可以100%确定TextView中的行数,而无需渲染它:

TextView textView = ...         //text view must be of fixed width

Paint paint = new Paint();
paint.setTextSize(yourTextViewTextSizePx);
paint.setTypeface(yourTextViewTypeface);

float textViewWidthPx = ...;

List<String> strings = splitWordsIntoStringsThatFit(yourText, textViewWidthPx, paint);
textView.setText(TextUtils.join("\n", strings);

int lineCount = strings.size();        //will be the same as textView.getLineCount()

答案 2
final Rect bounds = new Rect();
final Paint paint = new Paint();
paint.setTextSize(currentTextSize);
paint.getTextBounds(testString, 0, testString.length(), bounds);

现在,将文本的宽度与文本视图的宽度分开,以获得总行数。

final int numLines = (int) Math.ceil((float) bounds.width() / currentSize);

currentSize :将在其中呈现文本的视图的预期大小。尺寸不应超过屏幕宽度。


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