如果我理解你的问题，一种方法是自适应地休眠线程，类似于在Java中完成视频播放。如果您知道自己想要 50% 的核心利用率，则您的算法应休眠约 0.5 秒 - 可能分布在一秒内（例如，0.25 秒计算，0.25 秒睡眠，例如 t.c.）。这是我的视频播放器的一个例子。
long starttime = 0; // variable declared
//...
// for the first time, remember the timestamp
if (frameCount == 0) {
starttime = System.currentTimeMillis();
}
// the next timestamp we want to wake up
starttime += (1000.0 / fps);
// Wait until the desired next time arrives using nanosecond
// accuracy timer (wait(time) isn't accurate enough on most platforms)
LockSupport.parkNanos((long)(Math.max(0,
starttime - System.currentTimeMillis()) * 1000000));
此代码将根据帧/秒值休眠。
若要限制内存使用量，可以将对象创建包装到工厂方法中，并使用某种具有有限允许值的信号量作为字节来限制估计的总对象大小（您需要估计各种对象的大小以配给信号量）。
package concur;
import java.util.Random;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Semaphore;
import java.util.concurrent.TimeUnit;
public class MemoryLimited {
private static Semaphore semaphore = new Semaphore(1024 * 1024, true);
// acquire method to get a size length array
public static byte[] createArray(int size) throws InterruptedException {
// ask the semaphore for the amount of memory
semaphore.acquire(size);
// if we get here we got the requested memory reserved
return new byte[size];
}
public static void releaseArray(byte[] array) {
// we don't need the memory of array, release
semaphore.release(array.length);
}
// allocation size, if N > 1M then there will be mutual exclusion
static final int N = 600000;
// the test program
public static void main(String[] args) {
// create 2 threaded executor for the demonstration
ExecutorService exec = Executors.newFixedThreadPool(2);
// what we want to run for allocation testion
Runnable run = new Runnable() {
@Override
public void run() {
Random rnd = new Random();
// do it 10 times to be sure we get the desired effect
for (int i = 0; i < 10; i++) {
try {
// sleep randomly to achieve thread interleaving
TimeUnit.MILLISECONDS.sleep(rnd.nextInt(100) * 10);
// ask for N bytes of memory
byte[] array = createArray(N);
// print current memory occupation log
System.out.printf("%s %d: %s (%d)%n",
Thread.currentThread().getName(),
System.currentTimeMillis(), array,
semaphore.availablePermits());
// wait some more for the next thread interleaving
TimeUnit.MILLISECONDS.sleep(rnd.nextInt(100) * 10);
// release memory, no longer needed
releaseArray(array);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
};
// run first task
exec.submit(run);
// run second task
exec.submit(run);
// let the executor exit when it has finished processing the runnables
exec.shutdown();
}
}
