凌空请求队列超时

android java android-volley connection-timeout

2022-09-01 03:24:32

RequestQueue mRequestQueue = Volley.newRequestQueue(getApplicationContext());
mRequestQueue.add(new JsonObjectRequest(Method.GET, cityListUrl, null, new Listener<JSONObject>() 
{
    public void onResponse(JSONObject jsonResults) 
    {
        //Any Call
    }
}, new ErrorListener()
   {
        public void onErrorResponse(VolleyError arg0) 
        {
            //Any Error log
        }
   }
));

这是我的请求调用，我想更改或设置请求的超时。无论如何都有可能吗？

答案 1

您应该设置请求的重试策略：

myRequest.setRetryPolicy(new DefaultRetryPolicy(
                MY_SOCKET_TIMEOUT_MS, 
                DefaultRetryPolicy.DEFAULT_MAX_RETRIES, 
                DefaultRetryPolicy.DEFAULT_BACKOFF_MULT));

这会将您的代码更改为：

RequestQueue mRequestQueue = Volley.newRequestQueue(getApplicationContext());
JsonObjectRequest request = new JsonObjectRequest(Method.GET, cityListUrl, null, new
    Listener<JSONObject>() {
        public void onResponse(JSONObject jsonResults) {
            //Any Call
        }
    }, new ErrorListener(){
        public void onErrorResponse(VolleyError arg0) {
            //Any Error log
        }
    }
);


int socketTimeout = 30000;//30 seconds - change to what you want
RetryPolicy policy = new DefaultRetryPolicy(socketTimeout, DefaultRetryPolicy.DEFAULT_MAX_RETRIES, DefaultRetryPolicy.DEFAULT_BACKOFF_MULT);
request.setRetryPolicy(policy);
mRequestQueue.add(request);

如果您刚刚开始使用Volley，则可能需要考虑使用droidQuery，它更易于配置：

int socketTimeout = 30000;
$.ajax(new AjaxOptions().url(cityListUrl)
                        .timeout(socketTimeout)
                        .success(new Function() {
                            public void invoke($ d, Object... args) {
                                JSONObject jsonResults = (JSONObject) args[0];
                                //Any call
                            }
                        })
                        .error(new Function() {
                            public void invoke($ d, Object... args) {
                                AjaxError error = (AjaxError) args[0];
                                Log.e("Ajax", error.toString());
                            }
                        }));

答案 2

类似的东西

RetryPolicy retryPolicy = new DefaultRetryPolicy(
    YOUR_TIMEOUT_MS,
    YOUT_MAX_RETRIES,
    YOUR_BACKOFF_MULT
);

JsonObjectRequest request = new JsonObjectRequest(...);
request.setRetryPolicy(retryPolicy);

或者你可以实现自己的.RetryPolicy