GSON - 特定情况下的自定义序列化程序

2022-09-01 04:09:44

我有这个模式:

public class Student {
       public String name;
       public School school;
}

public class School {
       public int id;
       public String name;
}
public class Data {
      public ArrayList<Student> students;
      public ArrayList<School> schools;
}

我想用Gson序列化Data对象,并得到类似的东西:

{ "students": [{ 
                 "name":"name1",
                 "school": "1"          //the id of the scool, not its entire Json
              }],
  "school": [{                        //the entire JSON
              "id" : "1",
              "name": "schoolName"
            }]
}

为此,我必须对学生部分使用自定义序列化程序,以便Gson仅打印学校的ID。但对于学校来说,我必须有命名序列化器。

如何只用一个 Gson 对象完成所有操作?


答案 1

您可以编写自定义序列化程序,如下所示:

public class StudentAdapter implements JsonSerializer<Student> {

 @Override
 public JsonElement serialize(Student src, Type typeOfSrc,
            JsonSerializationContext context) {

        JsonObject obj = new JsonObject();
        obj.addProperty("name", src.name);
        obj.addProperty("school", src.school.id);

        return obj;
    }
}

答案 2

当然,无论你要在哪里序列化这个对象,你都需要把它添加到Gson中,如下所示:

Gson gson = new GsonBuilder()
    .registerTypeAdapter(Student.class, new StudentAdapter())
    .create();
return gson.toJson([YOUR_OBJECT_TO_BE_SERIALIZED]);