我想知道如何在Spring MVC应用程序中使用Spring Validator（不是注释）来验证表单中的嵌套对象列表。
class MyForm() {
String myName;
List<TypeA> listObjects;
}
class TypeA() {
String number;
String value;
}
如何创建MyFormValidator来验证列表对象并为TypeA的数量和值添加错误消息。
对于嵌套验证，可以执行以下操作：
public class MyFormValidator implements Validator {
private TypeAValidator typeAValidator;
@Override
public boolean supports(Class clazz) {
return MyForm.class.equals(clazz);
}
@Override
public void validate(Object target, Errors errors) {
MyForm myForm = (MyForm) target;
typeAValidator = new TypeAValidator();
int idx = 0;
for (TypeA item : myForm.getListObjects()) {
errors.pushNestedPath("listObjects[" + idx + "]");
ValidationUtils.invokeValidator(this.typeAValidator, item, errors);
errors.popNestedPath();
idx++;
...
}
...
}
}
public class TypeAValidator implements Validator{
@Override
public boolean supports(Class<?> clazz) {
return TypeA.class.isAssignableFrom(clazz);
}
@Override
public void validate(Object target, Errors errors) {
TypeA objTypeA = (TypeA)target;
ValidationUtils.rejectIfEmpty(errors, "number", "number.notEmpty");
}
}
希望这有帮助。
public class MyFormValidator implements Validator {
@Override
public boolean supports(Class clazz) {
return MyForm.class.equals(clazz);
}
@Override
public void validate(Object target, Errors errors) {
MyForm myForm = (MyForm) target;
for (int i = 0; i < myForm.getListObjects().size(); i++) {
TypeA typeA = myForm.getListObjects().get(i);
if(typeAHasAnErrorOnNumber) {
errors.rejectValue("listObjects[" + i + "].number", "your_error_code");
}
...
}
...
}
}
有趣的链接 ：
