Java：将 int 转换为 InetAddress

经过测试和工作：

int ip  = ... ;
String ipStr = 
  String.format("%d.%d.%d.%d",
         (ip & 0xff),   
         (ip >> 8 & 0xff),             
         (ip >> 16 & 0xff),    
         (ip >> 24 & 0xff));

这应该有效：

int ipAddress = ....
byte[] bytes = BigInteger.valueOf(ipAddress).toByteArray();
InetAddress address = InetAddress.getByAddress(bytes);

您可能必须交换字节数组的顺序，我无法确定数组是否将以正确的顺序生成。