使用 Web.xml配置嵌入式码头?

2022-09-01 10:49:59

我正在尝试与我的Web应用程序以及带有嵌入式码头的独立jar文件产生战争。对于嵌入式码头(jar文件分发),我添加了一个 servlet,如下所示:

public static void main(String[] args) throws Exception {
    Server server = new Server(8080);

    ServletContextHandler context = new ServletContextHandler(ServletContextHandler.SESSIONS);
    context.setContextPath("/");
    server.setHandler(context);

    context.addServlet(new ServletHolder(new HelloServlet()),"/*");

    server.start();
    server.join();
}

war 文件分发使用 web.xml文件,该文件在 Web 应用程序部分中包含以下内容:

<servlet>
    <servlet-class>com.example.HelloServlet</servlet-class>
    <servlet-name>SimplestServer</servlet-name>
</servlet>
<servlet-mapping>
    <servlet-name>HelloServlet</servlet-name>
    <url-pattern>/*</url-pattern>
</servlet-mapping>

这有效。但是,我想摆脱这两种方法之间的重复。也就是说,当我添加一个新的servlet时,我希望只能在一个位置配置它。我可以从嵌入式码头加载和使用.xml web 文件吗?


答案 1

Use a org.eclipse.jetty.webapp.WebAppContext

例:

package jetty;

import org.eclipse.jetty.server.Server;
import org.eclipse.jetty.webapp.WebAppContext;

public class OnWebApp
{
    public static void main(String[] args) throws Exception
    {
        // Create a basic jetty server object that will listen on port 8080.
        // Note that if you set this to port 0 then a randomly available port
        // will be assigned that you can either look in the logs for the port,
        // or programmatically obtain it for use in test cases.
        Server server = new Server(8080);

        // The WebAppContext is the entity that controls the environment in
        // which a web application lives and breathes. In this example the
        // context path is being set to "/" so it is suitable for serving
        // root context requests and then we see it setting the location of
        // the war. A whole host of other configurations are available,
        // ranging from configuring to support annotation scanning in the
        // webapp (through PlusConfiguration) to choosing where the webapp
        // will unpack itself.
        WebAppContext webapp = new WebAppContext();
        webapp.setContextPath("/");
        webapp.setWar("path/to/my/test.war");

        // A WebAppContext is a ContextHandler as well so it needs to be set to
        // the server so it is aware of where to send the appropriate requests.
        server.setHandler(webapp);

        // Start things up! By using the server.join() the server thread will
        // join with the current thread.
        // See http://docs.oracle.com/javase/1.5.0/docs/api/java/lang/Thread.html#join()
        // for more details.
        server.start();
        server.join();
    }
}

请注意,您将构建一个普通的 WAR 文件,并将其与 Jetty 一起使用。

如果您有特殊要求,例如注释扫描或JNDI,那么您需要进入配置规范。

// Enable parsing of jndi-related parts of web.xml and jetty-env.xml
org.eclipse.jetty.webapp.Configuration.ClassList classlist =
   org.eclipse.jetty.webapp.Configuration.ClassList.setServerDefault(server);

// Enable JNDI
classlist.addAfter("org.eclipse.jetty.webapp.FragmentConfiguration",
   "org.eclipse.jetty.plus.webapp.EnvConfiguration",
   "org.eclipse.jetty.plus.webapp.PlusConfiguration");

// Enable Annotation Scanning
classlist.addBefore("org.eclipse.jetty.webapp.JettyWebXmlConfiguration",
  "org.eclipse.jetty.annotations.AnnotationConfiguration");

有关 WebAppContext 中更详细的示例,请参阅 ServerWithAnnotations 示例。

另请注意,使用此技术,您还将拥有所有 webapp 类装入器规则。这意味着您将有一个用于web应用程序的类加载器和另一个用于服务器的类加载器。理解这一点很重要。

您可以对类装入器的WebAppContext进行一些调整,但您无法消除它们,只能控制它们的行为方式。

WebAppContext webapp = new WebAppContext();
// ... various setup of the webapp ...
// Flip the classloader priority from servlet spec where webapp is first to
// Standard java behavior of parent (aka Server classloader) is first.
webapp.setParentLoaderPriority(true);

另请参阅:


答案 2

我最终使用了Joakim的方法,但指向webapp目录而不是war文件。

public static void main(String[] args) throws Exception {
    Server server = new Server(8080);

    String rootPath = SimplestServer.class.getClassLoader().getResource(".").toString();
    WebAppContext webapp = new WebAppContext(rootPath + "../../src/main/webapp", "");
    server.setHandler(webapp);

    server.start();
    server.join();
}

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