使用进度条的长时间运行的进程示例 PlayFramework 2

2022-09-02 01:45:06

我正在尝试实现一个长时间运行的后台进程,该进程在用户访问页面时生成。我想显示任务的进度,就像在此示例中一样:http://web.archive.org/web/20130122091205/http://www.lunatech-research.com/archives/2011/10/31/progressbar-jqueryui-websockets-playframework

有谁知道PlayFramework 2.0(使用内置AKKA)的教程?这个是针对1.2的


答案 1

在阅读了所有适用于Java的Akka文档 http://doc.akka.io/docs/akka/2.0.1/intro/getting-started-first-java.html 之后,我想出了这个似乎效果很好。

系统的工作原理是首先创建一个唯一的Actor来处理“报告”(当加载生成页面时)。此执行组件生成一个子执行组件,该子执行组件将其进度报告回父执行组件。然后通过 JavaScript 轮询父角色以获取子线程的状态。

一旦子项完成,它就会终止,一旦父项检测到子项完成,它就会自行终止。

以下是所有代码,如果我以错误的方式进行此操作,请随时将我拆开!(是否可以在 Actor 中存储状态?!?)

控制器代码:

public class Application extends Controller {


public static Result generateReport()
{
    //create akka job

    //we should really create the actor with UUID name so that someone can't guess
    //and use the API to view the status of other peoples jobs, it be fairly easy
    //to guess as it goes $a,$b,$c etc...
   ActorRef myActor = Akka.system().actorOf(new Props(MyGeneratorMaster.class));

   System.out.println( myActor.path());
    myActor.tell(new ConfigMessage("blarg message"));

    return ok(generating.render("blarg","title",myActor.path().name()));
}

public static Result status(String uuid)
{
    uuid =  "akka://application/user/"+uuid;
    ActorRef myActor = Akka.system().actorFor(uuid);

    if(myActor.isTerminated())
    {
               return ok("Report Generated - All Actors Terminated") ;
    }
    else
    {

        return async(
                Akka.asPromise(ask(myActor,new StatusMessage(), 3000)).map(
                        new F.Function<Object,Result>() {
                            public Result apply(Object response) {

                                if(response instanceof ResultMessage)
                                {
                                    return ok(((ResultMessage) response).getResult());
                                }
                                return ok(response.toString());
                            }
                        }
                )
        );

    }
}

大师级演员:

public class MyGeneratorMaster extends UntypedActor {

    private int completed = 0;

    @Override
    public void postStop() {
        super.postStop();   
        System.out.println("Master Killed");
    }

    @Override
    public void onReceive(Object message) throws Exception {
        if (message instanceof actors.messages.ConfigMessage) {
            ConfigMessage config = (ConfigMessage) message;

            System.out.println("Received Config:" + config.getConfig());

            //Need to spawn child actor here..
            ActorRef child = this.getContext().actorOf(new Props(MyGeneratorChildWorker.class));

            //make the child thread do stuff
            child.tell(new ConfigMessage("doSomething!"));

            child.tell(akka.actor.PoisonPill.getInstance());//kill the child after the work is complete...

        } else if (message instanceof StatusUpdate) {
            System.out.println("Got Status Update");
            completed = ((StatusUpdate) message).getProgress();
        } else if (message instanceof StatusMessage) {
            System.out.println("Got Status Message");
            getSender().tell(new ResultMessage("Status: " + completed + "%"), getSelf());

            if(completed == 100)
            {
                //kill this actor, we're done!
                //could also call stop...
                this.getSelf().tell(akka.actor.PoisonPill.getInstance());
            }
        } else {
            System.out.println("unhandled message"+message.toString());
            unhandled(message);
        }

    }
}

儿童演员:

public class MyGeneratorChildWorker extends UntypedActor {

    @Override
    public void postStop() {
        super.postStop();    
        System.out.println("Child Killed");
    }

    @Override
    public void onReceive(Object message) throws Exception {

        if (message instanceof ConfigMessage) {

            System.out.println("Created Child Worker");

            System.out.println("Doing Work:");
            try {

                for (int i = 0; i <= 100; i++) {


                    //update parent
                    this.context().parent().tell(new StatusUpdate(i));
                    long j = 1;
                     //waste loads of cpu cycles
                    while (j < 1E8) {
                        j = j + 1;
                    }
                }
            } catch (Exception ex) {

            }
            System.out.println("Done Work:");


        } else
            unhandled(message);
    }
}

带有长轮询 JavaScript 的视图页面:

@(message: String)(title: String)(id: String)@main(title) {

<h2>@message</h2>

        <script type="text/javascript">

            function getPercentage()
            {

                $.ajax({
                    type: "GET",
                    url: "/status/@id",
                    dataType: "html",
                    success: function(html)
                        {
                        $('#status').html(html);


                        }
                });

            }

            $(document).ready(function() {


            setInterval("getPercentage()",100);
            });



        </script>

        <div id="status">

        </div>

}

答案 2

推荐