Java 树，用于表示路径列表中的文件系统（文件/目录）

感谢您的所有回答。我做了我的工作实现。我认为我需要改进它，以便在向树结构中添加元素时通过更多的缓存来使其更好地工作。

正如我所说，我需要的是一个结构，让我能够拥有FS的“虚拟”表现。

MXMTree.java

public class MXMTree {

    MXMNode root;
    MXMNode commonRoot;

    public MXMTree( MXMNode root ) {
        this.root = root;
        commonRoot = null;
    }

    public void addElement( String elementValue ) { 
        String[] list = elementValue.split("/");

        // latest element of the list is the filename.extrension
        root.addElement(root.incrementalPath, list);

    }

    public void printTree() {
        //I move the tree common root to the current common root because I don't mind about initial folder
        //that has only 1 child (and no leaf)
        getCommonRoot();
        commonRoot.printNode(0);
    }

    public MXMNode getCommonRoot() {
        if ( commonRoot != null)
            return commonRoot;
        else {
            MXMNode current = root;
            while ( current.leafs.size() <= 0 ) {
                current = current.childs.get(0);
            }
            commonRoot = current;
            return commonRoot;
        }

    }


}

MXMNode.java

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;


public class MXMNode {

    List<MXMNode> childs;
    List<MXMNode> leafs;
    String data;
    String incrementalPath;

    public MXMNode( String nodeValue, String incrementalPath ) {
        childs = new ArrayList<MXMNode>();
        leafs = new ArrayList<MXMNode>();
        data = nodeValue;
        this. incrementalPath = incrementalPath;
    }

    public boolean isLeaf() {
        return childs.isEmpty() && leafs.isEmpty();
    }

    public void addElement(String currentPath, String[] list) {

        //Avoid first element that can be an empty string if you split a string that has a starting slash as /sd/card/
        while( list[0] == null || list[0].equals("") )
            list = Arrays.copyOfRange(list, 1, list.length);

        MXMNode currentChild = new MXMNode(list[0], currentPath+"/"+list[0]);
        if ( list.length == 1 ) {
            leafs.add( currentChild );
            return;
        } else {
            int index = childs.indexOf( currentChild );
            if ( index == -1 ) {
                childs.add( currentChild );
                currentChild.addElement(currentChild.incrementalPath, Arrays.copyOfRange(list, 1, list.length));
            } else {
                MXMNode nextChild = childs.get(index);
                nextChild.addElement(currentChild.incrementalPath, Arrays.copyOfRange(list, 1, list.length));
            }
        }
    }

    @Override
    public boolean equals(Object obj) {
        MXMNode cmpObj = (MXMNode)obj;
        return incrementalPath.equals( cmpObj.incrementalPath ) && data.equals( cmpObj.data );
    }

    public void printNode( int increment ) {
        for (int i = 0; i < increment; i++) {
            System.out.print(" ");
        }
        System.out.println(incrementalPath + (isLeaf() ? " -> " + data : "")  );
        for( MXMNode n: childs)
            n.printNode(increment+2);
        for( MXMNode n: leafs)
            n.printNode(increment+2);
    }

    @Override
    public String toString() {
        return data;
    }


}

测试.java用于测试代码

public class Test {

    /**
     * @param args
     */
    public static void main(String[] args) {

        String slist[] = new String[] { 
                "/mnt/sdcard/folder1/a/b/file1.file", 
                "/mnt/sdcard/folder1/a/b/file2.file", 
                "/mnt/sdcard/folder1/a/b/file3.file", 
                "/mnt/sdcard/folder1/a/b/file4.file",
                "/mnt/sdcard/folder1/a/b/file5.file", 
                "/mnt/sdcard/folder1/e/c/file6.file", 
                "/mnt/sdcard/folder2/d/file7.file", 
                "/mnt/sdcard/folder2/d/file8.file", 
                "/mnt/sdcard/file9.file" 
        };

        MXMTree tree = new MXMTree(new MXMNode("root", "root"));
        for (String data : slist) {
            tree.addElement(data);
        }

        tree.printTree();
    }

}

请告诉我，如果你有一些关于改进的好建议:)

我自己实现了一个挑战的解决方案，它可以作为GitHubGist使用。

我在 DirectoryNode 中表示文件系统层次结构的每个节点。一个帮助者方法 createDirectoryTree（String[] filesystemList） 创建一个 direcotry-tree。

下面是 GitHubGist 中包含的用法示例。

final String[] list = new String[]{
  "/mnt/sdcard/folder1/a/b/file1.file",
  "/mnt/sdcard/folder1/a/b/file2.file",
  "/mnt/sdcard/folder1/a/b/file3.file",
  "/mnt/sdcard/folder1/a/b/file4.file",
  "/mnt/sdcard/folder1/a/b/file5.file",
  "/mnt/sdcard/folder1/e/c/file6.file",
  "/mnt/sdcard/folder2/d/file7.file",
  "/mnt/sdcard/folder2/d/file8.file",
  "/mnt/sdcard/file9.file"
};

final DirectoryNode directoryRootNode = createDirectoryTree(list);

System.out.println(directoryRootNode);

System.out.println -output 是：

  {value='mnt', children=[{value='sdcard', children=[{value='folder1', 
  children=[{value='a', children=[{value='b', children=[{value='file1.file', 
  children=[]}, {value='file2.file', children=[]}, {value='file3.file', 
  children=[]}, {value='file4.file', children=[]}, {value='file5.file', 
  children=[]}]}]}, {value='e', children=[{value='c', 
  children=[{value='file6.file', children=[]}]}]}]}, 
  {value='folder2', children=[{value='d', children=[{value='file7.file', 
  children=[]}, {value='file8.file', children=[]}]}]}, 
  {value='file9.file', children=[]}]}]}