Java 的“Parallel.For”?

2022-08-31 13:27:37

我想知道是否有一个Parallel.For相当于Java的.net版本?

如果有人能举个例子吗?谢谢!


答案 1

我想最接近的是:

ExecutorService exec = Executors.newFixedThreadPool(SOME_NUM_OF_THREADS);
try {
    for (final Object o : list) {
        exec.submit(new Runnable() {
            @Override
            public void run() {
                // do stuff with o.
            }
        });
    }
} finally {
    exec.shutdown();
}

根据 TheLQ 的注释,您将SUM_NUM_THREADS设置为Runtime.getRuntime().availableProcessors();

编辑:决定添加一个基本的“Parallel.For”实现

public class Parallel {
    private static final int NUM_CORES = Runtime.getRuntime().availableProcessors();

    private static final ExecutorService forPool = Executors.newFixedThreadPool(NUM_CORES * 2, new NamedThreadFactory("Parallel.For"));

    public static <T> void For(final Iterable<T> elements, final Operation<T> operation) {
        try {
            // invokeAll blocks for us until all submitted tasks in the call complete
            forPool.invokeAll(createCallables(elements, operation));
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
    }

    public static <T> Collection<Callable<Void>> createCallables(final Iterable<T> elements, final Operation<T> operation) {
        List<Callable<Void>> callables = new LinkedList<Callable<Void>>();
        for (final T elem : elements) {
            callables.add(new Callable<Void>() {
                @Override
                public Void call() {
                    operation.perform(elem);
                    return null;
                }
            });
        }

        return callables;
    }

    public static interface Operation<T> {
        public void perform(T pParameter);
    }
}

并行的示例用法。对于

// Collection of items to process in parallel
Collection<Integer> elems = new LinkedList<Integer>();
for (int i = 0; i < 40; ++i) {
    elems.add(i);
}
Parallel.For(elems, 
 // The operation to perform with each item
 new Parallel.Operation<Integer>() {
    public void perform(Integer param) {
        System.out.println(param);
    };
});

我想这个实现真的更类似于Parallel.ForEach。

编辑如果有人感兴趣,我会把它放在GitHub上。Parallel For on GitHub


答案 2

MLaw的解决方案是一个非常实用的Parallel.ForEach。我添加了一些修改来制作一个 Parallel.For。

public class Parallel
{
static final int iCPU = Runtime.getRuntime().availableProcessors();

public static <T> void ForEach(Iterable <T> parameters,
                   final LoopBody<T> loopBody)
{
    ExecutorService executor = Executors.newFixedThreadPool(iCPU);
    List<Future<?>> futures  = new LinkedList<Future<?>>();

    for (final T param : parameters)
    {
        Future<?> future = executor.submit(new Runnable()
        {
            public void run() { loopBody.run(param); }
        });

        futures.add(future);
    }

    for (Future<?> f : futures)
    {
        try   { f.get(); }
        catch (InterruptedException e) { } 
        catch (ExecutionException   e) { }         
    }

    executor.shutdown();     
}

public static void For(int start,
                   int stop,
               final LoopBody<Integer> loopBody)
{
    ExecutorService executor = Executors.newFixedThreadPool(iCPU);
    List<Future<?>> futures  = new LinkedList<Future<?>>();

    for (int i=start; i<stop; i++)
    {
        final Integer k = i;
        Future<?> future = executor.submit(new Runnable()
        {
            public void run() { loopBody.run(k); }
        });     
        futures.add(future);
    }

    for (Future<?> f : futures)
    {
        try   { f.get(); }
        catch (InterruptedException e) { } 
        catch (ExecutionException   e) { }         
    }

    executor.shutdown();     
}
}

public interface LoopBody <T>
{
    void run(T i);
}

public class ParallelTest
{
int k;  

public ParallelTest()
{
    k = 0;
    Parallel.For(0, 10, new LoopBody <Integer>()
    {
        public void run(Integer i)
        {
            k += i;
            System.out.println(i);          
        }
    });
    System.out.println("Sum = "+ k);
}

public static void main(String [] argv)
{
    ParallelTest test = new ParallelTest();
}
}

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